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kiruha [24]
3 years ago
8

The given series has six terms. what is the sum of the terms of the series? 10 + 25 + 40 + . . . + 85

Mathematics
2 answers:
tatiyna3 years ago
4 0
10+25+40+55+70+85
           35+95+155
             130+155
                 285

answer: 285
              
cupoosta [38]3 years ago
4 0

Answer with Step-by-step explanation:

The sum of first n terms of an arithmetic progression is given by:

S(n)=\dfrac{n}{2}\times (A1+An)

10+25+40+...+85

Since, the terms have a common difference of 15

So, it is an arithmetic progression of n=6 terms with first term A1=10

and A6=85

We have to find S(6)

S(6)=\dfrac{6}{2}\times (10+85)

             = 285

Hence, the sum of the terms of the series 10 + 25 + 40 + . . . + 85 is:

285

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\sum_{i=1}^n x^2_i =50^2 + 55^2 + 50^2 + 79^2 + 44^2 + 37^2 + 70^2 + 45^2 + 49^2=26897

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S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=26897-\frac{479^2}{9}=1403.556

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