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The function has a horizontal asymptote at y = 3.
The function has a vertical asymptote at x = -3.
The function has a vertical intercept of 1.
The function has a zero of x = -2.
Because the function has a zero at x = -2, and a vertical asymptote at x = -3, therefore
Write the function in the form
y =
As x → ∞, y → k.
Because a horizontal asymptote exists at y = 3, therefore k = 3.
A vertical intercept exists at y = 1.
The function is
Answer:
The function has a vertical asymptote at x = -3.
The function has a vertical intercept of 1.
The function has a zero of x = -2.
Because the function has a zero at x = -2, and a vertical asymptote at x = -3, therefore
Write the function in the form
y =
As x → ∞, y → k.
Because a horizontal asymptote exists at y = 3, therefore k = 3.
A vertical intercept exists at y = 1.
The function is
Answer:
Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
