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3 years ago

13

Jeremy can row 3/8 of a mile in 1/4 of an hour.

1 answer:

Elza [17]3 years ago

6 0

Answer:

3/2 mph

Step-by-step explanation:

$\frac{3}{8}$ = $\frac{r}{4}$

cross-multiply: 8r = 12

r = 12/8 or 1.5 mph

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Drag the tiles to the correct boxes to complete the pairs. Match the systems of equations with their solutions.

Oksanka [162]

Answer:

See explanation for matching pairs

Step-by-step explanation:

Equations

(1)

$x - y = 25$

$2x + 3y = 180$

(2)

$2x - 3y = -5$

$11x + y = 550$

(3)

$x - y = 19$

$-12x + y = 168$

Solutions

$(-17,-36)$

$(47, 33)$

$(51, 26)$

Required

Match equations with solutions

(1) $x - y = 25$ and $2x + 3y = 180$

Make x the subject in: $x - y = 25$

$x = 25 + y$

Substitute $x = 25 + y$ in $2x + 3y = 180$

$2(25 + y) + 3y = 180$

$50 + 2y + 3y = 180$

$50 + 5y = 180$

Collect like terms

$5y = 180-50$

$5y = 130$

Solve for y

$y =26$

Recall that: $x = 25 + y$

$x = 25 + 26$

$x = 51$

So:

$(x,y) = (51,26)$

(2) $2x - 3y = -5$ and $11x + y = 550$

Make y the subject in $11x + y = 550$

$y = 550 - 11x$

Substitute $y = 550 - 11x$ in $2x - 3y = -5$

$2x - 3(550 - 11x) = -5$

$2x - 1650 + 33x = -5$

Collect like terms

$2x + 33x = -5+1650$

$35x = 1645$

Solve for x

$x = 47$

Solve for y in $y = 550 - 11x$

$y = 550 - 11 * 47$

$y = 550 - 517$

$y = 33$

So:

$(x,y) = (47,33)$

(3)

$x - y = 19$ and $-12x + y = 168$

Make y the subject in $-12x + y = 168$

$y = 168 + 12x$

Substitute $y = 168 + 12x$ in $x - y = 19$

$x - 168 - 12x = 19$

Collect like terms

$x -12x = 168 + 19$

$-11x = 187$

Solve for x

$x = -17$

Solve for y in $y = 168 + 12x$

$y =168-12 *17$

$y =-36$

So:

$(x,y) = (-17,-36)$

4 0

3 years ago