We can solve with a system of equations, and use c for the amount of cans of soup and f for the amount of frozen dinners.
The first equation will represent the amount of sodium. We know the (sodium in one can times the number of cans) plus (sodium in one frozen dinner times the number of dinners) is the expression for the total sodium. We also know the total sodium is 4450, so:
250c + 550f = 4450
The second equation is to find how many of each item are purchased:
c + f = 13
Solve for c in the second equation:
c = 13 - f
Plug this in for c in the first equation:
250(13-f) + 550f = 4450
3250 - 250f + 550f = 4450
300f = 1200
f = 4
Now plug the value for f into the second equation:
c + 4 = 13
c = 9
The answer is 9 cans of soups and 4 frozen dinners.
I hope this helps you
x =4
f (4)= 4.4+7 = 16+7=23
f (4)= 4.4-7=16-7=9
Answer:
<h3>The nth term
Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>
Step-by-step explanation:
Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.
If the sum of the first two term is 24, then a/r + a = 24...(1)
and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)
Substtituting equation 1 into 2 we have;
24+ar = 26
ar = 2
a = 2/r ...(3)
Substituting a = 2/r into equation 1 will give;
(2/r))/r+2/r = 24
2/r²+2/r = 24
(2+2r)/r² = 24
2+2r = 24r²
1+r = 12r²
12r²-r-1 = 0
12r²-4r+3r -1 = 0
4r(3r-1)+1(3r-1) = 0
(4r+1)(3r-1) = 0
r = -1/4 0r 1/3
Since a= 2/r then a = 2/(-1/4)or a = 2/(1/3)
a = -8 or 6
All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of a geometric sequence is expressed as
if r = -1/4 and a = -8
Tn = -8(-1/4)^(n-1)
if r = 1/3 and a = 6
Tn = 6(1/3)^(n-1)
The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms
Answer:
A
Step-by-step explanation:
Slope intercept form is
y=mx+b
y is y
3x is mx
and
b is 2
Answer:
I don't know what, I would like to know
