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3 years ago

PLZZZZ HELPPPPP In your own words, define: point, line, ray, segment, plane.

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

point - a specific spot on the graph

line - a ray with both sides never ending

ray - a line with one side ending

segment - a specific piece of the line

plane - a never ending surface

Step-by-step explanation:

i took geometry last yearish

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For one English test, sandy had to answer 15 questions. Of these questions, she answered 80 percent of them correctly. How many

Rudik [331]

Answer:

Step-by-step explanation:

15×0.8= 12

you're multiplying the total number of questions with the score as a decimal

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3 years ago

The number of motor vehicles registered in millions in the US has grown as follows:

zysi [14]

Answer:

a) Figure attached

b) $r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989$

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989$

So then the correlation coefficient would be r =0.989

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2 years ago

Help I'm desperate it's near midnight and assignment due tomorrow rip me

andrey2020 [161]

The first one is categorical data
the second one is discrete numerical
and the third one is continuous numerical
i hope this helps you
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3 years ago

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