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Tanya [424]
2 years ago
6

Help me with these asap

Mathematics
1 answer:
IgorLugansk [536]2 years ago
3 0
Use the app that you can easily find answers on
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Q2) The isoscsles right triangle has 2 of it’s sides 10,10 it’s area is
nydimaria [60]

Answer:

Step-by-step explanation:

side a = 10

Area of isosceles triangle = \frac{\sqrt{3}a^{2}}{4}\\\\

           = \frac{\sqrt{3}*10*10}{4}\\\\=\sqrt{3}*5*5\\\\=25\sqrt{3}\\\\=25*1.732

             = 43.3 square units

3 0
3 years ago
Figure BCDE was transformed using the composition rx-axis ◦ T2,2. If point B on the pre-image lies at (3, 4), what are the coord
____ [38]

Answer:

The answer is "(5, -6)"

Step-by-step explanation:

Given:

The Pre-image line at point B is: (3, 4)

Solution:

\ rx-axis \circ \  T2,2 (3,4) \\\\\Rightarrow  \ rx-axis \ ( T2,2 (3,4) )\\\\ \Rightarrow \ rx-axis ( 5,6  ) \\\\ \Rightarrow  (5, -6)\\

The coordinates of B point is (5,-6).

5 0
3 years ago
Read 2 more answers
When considering order of operations (PEMDAS), addition will ALWAYS come before subtraction.
Sergeeva-Olga [200]

Parenthises

Exponent

Multiply

Divide

Add

Subtract

The answer is true because it comes before subtraction in the phrase PEMDAS.

7 0
3 years ago
Read 2 more answers
Maria solved an equation as shown below. 3 (x + 6) = 5 (x minus 4). 3 x + 18 = 5 x minus 20. 38 = 2 x. 19 = x.
KonstantinChe [14]

Answer:

i think it 5

Step-by-step explanation:

8 0
3 years ago
Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
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