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matrenka [14]
3 years ago
11

Determine the constant of variation for the direct variation given. Type a numerical answer in the space provided.

Mathematics
1 answer:
Andreyy893 years ago
5 0

Answer:

B. 4

Step-by-step explanation:

Determine the constant of variation for the direct variation given.

(0, 0), (3, 12), (9, 36)

A. 3

B. 4

C.12

Direct variation is given by:

y = kx

Where,

k = constant of variation

(3, 12)

x = 3; y = 12

y = kx

12 = k*3

12 = 3k

k = 12 / 3

k = 4

(9, 36)

x = 9; y = 36

y = kx

36 = k * 9

36 = 9k

k = 36 / 9

= 4

k = 4

Constant of the variation = 4

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Find the probability.
KATRIN_1 [288]

Using it's concept, it is found that there is a 0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 15 bottles.

  • 5 are orange, hence the is a 5/15 = 1/3 probability that the coach gets orange, hence P(A) = 1/3.
  • After the coach, there will be 14 bottles remaining, of which 4 are orange, hence the probability that the friend gets orange is of P(B) = 4/14 = 2/7.
  • For you, there will be 13 bottles remaining, of which 5 will be of fruit-punch, hence the probability you get fruit-punch is of P(C) = 5/13.

The probability of the three outcomes occurring is given by:

p = \frac{1}{3} \times \frac{2}{7} \frac{5}{13} = \frac{10}{273} = 0.0366

0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

6 0
1 year ago
In this equation, what is n?
raketka [301]
N is the variable, you solve by subtracting 6 from 20, getting n = 14.
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3 years ago
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Anni [7]

Hello!

1/4 is equal to 0.25. Let's divide below.

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When dividing by fractions, you multiply by the reciprocal. The reciprocal of 1/4 is 4, and 5(4)=20

Therefore, our answer is 20.

I hope this helps!

6 0
3 years ago
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