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melamori03 [73]
3 years ago
6

Please help! asap! i have no idea what it is and it’s worth a lot of points on my test!

Mathematics
1 answer:
beks73 [17]3 years ago
5 0
I haven’t done math in forever, do you want us to simplify it? Bc it would be 2x+8=-16=4x+6 but I’m not sure
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Oliver draws a line on his paper and from a point on the line draws a circle. He then measures the radius of his circle and cons
olasank [31]
Dye answer is The letter D
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3 years ago
One factor of f(x) = x3 − 14x2 + 61x − 84 is (x − 7). What are the zeros of the function?
Slav-nsk [51]

Answer:

-7

Step-by-step explanation:

Because zero is the x, so x=-7 then it's -7

8 0
3 years ago
Is it possible for three vectors of different magnitudes to add to zero?.
amid [387]

Answer:

No, it is not possible to obtain zero by adding two vectors of unequal magnitudes.

Explanation:

The Sum of two vectors can only be zero if they are equal in magnitude and opposite in direction. So no two vectors of unequal magnitude cannot be added to give a null vector. Three vectors of equal magnitude and making an angle 120 degrees with each other gives a zero resultant.

6 0
2 years ago
If the angles are represented in degrees, find both angles sin(x+76)=cos(3x+2)
poizon [28]

Step-by-step explanation:

x + 76 + 3x +  2 = 90

4x + 78 = 90

4x = 12

x = 3

Angle 1 is 79

Angle 2 is 11.

4 0
3 years ago
What is the sum of the infinite geometric series?<br><br> 120 + 20+ 10/3 + 5/9+...
Sergeu [11.5K]

Answer:

for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

Step-by-step explanation:

i) from the given series we can see that the first term is a_{1 } = 120.

ii) let the common ratio be r.

iii) the second term is 20 = 120 × r

   therefore r = 20 ÷ 120 = \dfrac{1}{6}

iv) the third term is \frac{10}{3} = 20 × r

    therefore r = \dfrac{10}{3} ÷ 20 = \dfrac{1}{6}

v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

6 0
3 years ago
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