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Anni [7]
2 years ago
7

An item on sale costs 25% of the original price. The original price was $55.

Mathematics
1 answer:
Firdavs [7]2 years ago
7 0

Answer:

$68.75 cents

Step-by-step explanation:

Given the following question:

25% of 55

In order to find the answer, we must first use the formula to calculate percentages to calculate 25% of 55, then we use that answer to add on the initial amount.

\frac{p\times n}{100}
\frac{25\times 55}{100} =25\times55=1375\div100=13.75
=13.75

<u>Now add:</u>
55+13.75=68.75
=68.75

After a 25% increase on an item that costs 55 dollars, the new sale price will cost "$68.75 cents."

Hope this helps.

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What is the distance from W to X?
Flauer [41]

Answer:

The answer is 35 miles.

Step-by-step explanation:

Let's assume that the distance from W to Y is x miles

Distance from W to X is 70 % of x =0.7*x

Given distance from X to Y is 15 miles.

x-15=0.7x

x-0.7x=15

0.3x=15

x=15/0.3

x=50miles

Thus the distance from W to Y is 50 miles and the distance from W to X is 50-15=35 miles

3 0
3 years ago
6. A pizza's original price is $11. It is on sale for $9.25. What percent off is it?
wolverine [178]

Solution:

<u>We know that:</u>

Original \ price = \$11

Sale \ price = \$9.25

\frac{9.25}{11} + \frac{1.75}{11} =100\%

<u>Simplify the equation to find the percent off:</u>

\frac{9.25}{11} + \frac{1.75}{11} =100\%

84\% + \bold{16\%} = 100\% \space\ \space\ \space\ \ \ \ \ [Rounded]

This means that the <u>original price</u> has decreased about 16%.

4 0
3 years ago
Please help me 33/2 + 3y/5 = 7y/10 + 15
8090 [49]

We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

8 0
2 years ago
Please help me solve them
deff fn [24]
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
8 0
3 years ago
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How to explain 3,482,000,000 in scientific notation
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3.482 x 10^9.
-the coefficient must be under 10, and in this case it is the "3". Then you count the places after that to get your exponent
7 0
3 years ago
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