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pogonyaev
3 years ago
10

If the following fraction is reduced, what will be the exponent on the p? -5p^5q^4/ 8p^2q^2

Mathematics
2 answers:
viktelen [127]3 years ago
6 0
<span>-5p^5q^4/ 8p^2q^2
= -5p^3q^2

</span><span>exponent on the p will be 3

answer
</span><span>C.3</span>
oksano4ka [1.4K]3 years ago
6 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}&#10;\qquad \qquad&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\qquad \qquad &#10;a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{-5p^5q^4}{8p^2q^2}\implies \cfrac{-5p^5q^4p^{-2}q^{-2}}{8}\implies \cfrac{-5p^5p^{-2}q^4q^{-2}}{8}&#10;\\\\\\&#10;\cfrac{-5p^{5-2}q^{4-2}}{8}\implies \cfrac{-5\boxed{p^3} q^2}{8}
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Tatiana [17]

For this case we have that by definition of properties of powers and roots, it is fulfilled that:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

n

a

m

=a

n

m

So:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {\frac {1} {2}} {4} x} = 9 ^ {\frac {1} {8} x}

4

9

2

1

x

=9

4

2

1

x

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8

1

x

So, we have to:

\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {1} {8} x}

4

9

2

1

x

=9

8

1

x

Answer:

9 ^ {\frac {1} {8} x}9

8

1

x

Option B

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Answer:

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x^{2} = \frac{40}{0.01}

x =\pm \sqrt{\frac{40}{0.01} }

x = \pm 63.246\,ft

Given that the parabola is symmetrical with respect to y-axis, then the length is two times the magnitude of the value found above, that is:

l = 2\cdot (63.246\,ft)

l = 126.492\,ft

The length of the bridge is 126.492 feet.

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