To figure this one out, my pre calculus teacher said to "plug and chug". Since you are adding each number to itself, A=-20, B=-10, C=0, and D=10. So your answer would be C.0
Answer:
(-5,-14)
Step-by-step explanation:
To find the solution of the system of two equations

equate right sides of these two equations:

Rewrite terms with x into the left side and without x into the right side:
![4x-2x=-4-6\\ \\2x=-10\ [\text{divide by 2}]\\ \\x=-5](https://tex.z-dn.net/?f=4x-2x%3D-4-6%5C%5C%20%5C%5C2x%3D-10%5C%20%5B%5Ctext%7Bdivide%20by%202%7D%5D%5C%5C%20%5C%5Cx%3D-5)
Substitute x=-5 into the first equation:
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The solution is (-5,-14)
Try this option:
1] P(S)=0.84;
2] P(S or C, but not both)=0.4;
3] P(C)=0.76;
4] P(S∪C)=0.6;
5] P(C, but not S)=0.16;
6] P(S∩C)=1.00.
Answer:
B. Age of student
D. Time taken to run 1 mile
Step-by-step explanation:
From the list of given options, only B and D satisfy the required condition.
One unique determinant of continuous data is that; they are measured and not counted.
Now, let's categorize option A to D into two
1. Counted data
2. Measured data
Options that fall into the category of measured data are said to be continuous data.
A. Concert attendance; The number of people in a concert is counted
B. The age of a student is measured (in years)
C. Number of pens in a box is counted
D. Time taken to run 1 mile is measured (in units like seconds, minutes, hours, etc...)
In summary; we have
Counted
A. Concert Attendance
C. Number of pens in a box
Measured
B. Age of a student
D. Time taken to run 1 mile
Hence, the continuous data are Age of a student and Time taken to run 1 mile
Answer:
divide the least common denominator by the original denominator