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Natalka [10]
3 years ago
14

You buy 4 balloons and 2 banners for $8. Your friend buys 6 balloons and 1 banner for $8.

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0

Answer:

Each balloon costs $1

Each banner costs $2

Step-by-step explanation:

First of all, let's write down the equation from this problem.

Let "y" be the cost of the ballon, and let "x" be the cost of a banner. Then the following is true from the question...

4y + 2x = 8

6y + x = 8

Now since both of them are equal to 8 both of them are equal to each other, and so we can get the following equation...

4y + 2x = 6y + x

2x - x = 6y - 4y

x = 2y

Now if we substitute 2y instead of x in one of the previous equations we will obtain...

6y + x = 8

6y + 2y = 8

8y = 8

y = 1

From the equation x = 2y we know that...

x = 2y

x = 2(1)

x = 2

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Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14
sertanlavr [38]

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<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

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<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

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3 years ago
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Marrrta [24]

Answer:

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Step-by-step explanation:

1800-270=1530 therefore answer is 1530

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lakkis [162]

Answer:

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Step-by-step explanation:

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Vertical angles are congruent, so the angle on the other side is also 80°.  Therefore:

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