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tiny-mole [99]
3 years ago
7

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY PLEASE HELP!

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

The Answer is 5/9 in the simplest form.

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There are 36 apples in a bag if Yuri takes out 6 of the apples in simplest form what fraction of the apples sis je take oyt of t
lord [1]
If she takes out six then the fraction is 6/36 then you just simplify dividing it by 6 which will give you 1/6.
5 0
3 years ago
Read 2 more answers
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
1 year ago
Can someone please help me. I need help on the 5 one
soldi70 [24.7K]

Answer:

The second option

Step-by-step explanation:

On the right hand side you have all the multiples of 4, on the left hand side you have 5

The multiples of four are ...,-8,-4,0,4,8,....

so the simbol that means that 5 is not an element of the multiples of four is the second option.

4 0
3 years ago
Sock hop (ExH). You have 10 pairs of socks, fi ve black and fi ve blue, but they are not paired up. Instead, they are all mixed
kvasek [131]

Answer:

Step-by-step explanation:

Total number of pairs of socks in a drawer = 10

Number of black pairs of socks = 5

Number of blue pairs of socks  = 5

A. If you picked 2 socks [black] and [blue] 3rd pick guarantees you will have one pair of either blue or black

Number of socks you pull out to guarantee that you have a pair of one color = 3 socks

B. If you want to pick 2 good pairs and your 6 picks are worst case, so 7th pick of the socks will give you good pair of two colors.

Number of socks you pull out to have two good pairs = 7 socks

C. If you want to have a pair of black socks your worst case will be you pick all 10 blue socks so another 2 socks must be black.

Number of socks you pull out to have two black socks = 12 socks

4 0
3 years ago
Answer plz helpppp me!!!!!!
balandron [24]
Vertical angles theorem
8 0
3 years ago
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