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Agata [3.3K]
3 years ago
9

absmiddle" class="latex-formula">
Mathematics
1 answer:
Shalnov [3]3 years ago
7 0
8-/x(x-4)/x-3
That should be it if you can’t understand it the whole equation after the eight is a fraction
You might be interested in
Please at least help me cause I have no idea
Blababa [14]

Answer:

Solving the given formula for v2 gives us:

a(t_2-t_1)+v_1 = v_2

Step-by-step explanation:

Solving an equation for a particular variable means that the variable has to be isolated on one side of the equation.

Given equation is:

a = \frac{v_2-v_1}{t_2-t_1}

Multiplying both sides by t2-t1

(t_2-t_1) . a = \frac{v_2-v_1}{t_2-t_1} . (t_2-t_1)\\a(t_2-t_1) = v_2-v_1

Adding v1 to both sides of the equation

a(t_2-t_1)+v_1 = v_2-v_1+v_1\\a(t_2-t_1)+v_1 = v_2

Hence,

Solving the given formula for v2 gives us:

a(t_2-t_1)+v_1 = v_2

8 0
3 years ago
The proportion of high school seniors who are married is 0.02. Suppose we take a random sample of 300 high school seniors; a.) F
cricket20 [7]

Answer:

a) Mean 6, standard deviation 2.42

b) 10.40% probability that, in our sample of 300, we find that 8 of the seniors are married.

c) 14.85% probability that we find less than 4 of the seniors are married.

d) 99.77% probability that we find at least 1 of the seniors are married

Step-by-step explanation:

For each high school senior, there are only two possible outcomes. Either they are married, or they are not. The probability of a high school senior being married is independent from other high school seniors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that:

n = 300, p = 0.02

a.) Find the mean and standard deviation of the sample count X who are married.

Mean

E(X) = np = 300*0.02 = 6

Standard deviation

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.02*0.98} = 2.42

b.) What is the probability that, in our sample of 300, we find that 8 of the seniors are married?

This is P(X = 8).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{300,8}.(0.02)^{8}.(0.98)^{292} = 0.1040

10.40% probability that, in our sample of 300, we find that 8 of the seniors are married.

c.) What is the probability that we find less than 4 of the seniors are married?

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{300,0}.(0.02)^{0}.(0.98)^{300} = 0.0023

P(X = 1) = C_{300,1}.(0.02)^{1}.(0.98)^{299} = 0.0143

P(X = 2) = C_{300,2}.(0.02)^{2}.(0.98)^{298} = 0.0436

P(X = 3) = C_{300,3}.(0.02)^{3}.(0.98)^{297} = 0.0883

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0023 + 0.0143 + 0.0436 + 0.0883 = 0.1485

14.85% probability that we find less than 4 of the seniors are married.

d.) What is the probability that we find at least 1 of the seniors are married?

Either no seniors are married, or at least 1 one is. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

From c), we have that P(X = 0) = 0.0023. So

0.0023 + P(X \geq 1) = 1

P(X \geq 1) = 0.9977

99.77% probability that we find at least 1 of the seniors are married

3 0
3 years ago
(7,3) a solution of y
nasty-shy [4]

Answer:

y=3

Step-by-step explanation:

3 0
3 years ago
Round the mixed number to the nearest 1/2. 4 2/3<br>A.4<br>B.4 1/2<br>C.5
IceJOKER [234]
2/3 is 0.6. 1/2 is 0.5.

so 0.6 is less than 0.75 and it will round up to 0.5, not to 1.

so 4 2/3 will round to 4 1/2.
6 0
4 years ago
Read 2 more answers
Helppppppppppppppppppppp
Nastasia [14]

Answer:

Step-by-step explanation:

1) 5 - [-5] = 5 + 5 = 10

2)8 - 13 = 8 + (-13) = -5

3) 12 +(-3) = 9

4) x + (-7) = 5

   x - 7 = 5

        x = 5 + 7

x = 12

We need to add 12 to (-7) to get 5

5) 7 - x = -5

    7 = -5 +x

  7 + 5 = x

    12 = x

We need to take away 12 to 7 to get (-5)

6) 7 - (-10) = 7 + 10 = 17

17° C

8 0
3 years ago
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