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2 years ago

How many centimetres are there in a metre

Mathematics

2 answers:

Anna35 [415]2 years ago

6 0

I believe it would be 100. Not sure tho

KIM [24]2 years ago

3 0

Step-by-step explanation:

your answer is 100 metres

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Fifth-grade students plant a class garden. They plant 7 1/6 rows of tomatoes and 3 1/2 rows of carrots. How many fewer rows of c

Nikitich [7]

Answer:

3 2/3

Step-by-step explanation:

7 1/6 - 3 1/2= 3 2/3

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2 years ago

HELP ASAP 50 POINTS

Andrei [34K]

It’s C because the y-intercept is where the point intersects on the y-axis and the slope goes up one and over 2 to the left making it negative

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2 years ago

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9. Eric guessed that Troop A was going to have 23 members in 2011 when they actually had 20. How much was Eric off by in his est

julia-pushkina [17]

Answer:The answer is D

Step-by-step explanation:

23 - 20=3

(3 ➗ 20) *100

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1 year ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

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2 years ago

{1, 5, 10, 15} {1, 3, 5, 7} Which of the following shows the union of the sets?

maria [59]

Answer:

{1, 5}

Step-by-step explanation:

the union is all the values in both sets. The only shared numbers in these two sets are 1, and 5. therefore, the union of the sets is {1, 5}

Hope this helps have a great day! <3

also, pls mark brainliest!!

7 0

2 years ago

How many centimetres are there in a metre​

How many centimetres are there in a metre