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Dima020 [189]
2 years ago
12

A, B, C, D, E and F are points on a circle. put crosses on the ends of the line that is a diameter of the circle

Mathematics
1 answer:
Step2247 [10]2 years ago
3 0

9514 1404 393

Answer:

  AD is the diameter

Step-by-step explanation:

Angles in a triangle have a sum of 180°, so inscribed angle B is 80° and inscribed angle E is 90°.

An inscribed angle subtends an arc that is twice its measure, so arcs ABD and AED are both 180°. That makes chord AD a diameter.

Points A and D need your cross markings. AD is a diameter of the circle.

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A circle is centered at the point (7,1) and passes through the point (8,7). what is the radius
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Easy

the radius is the distance from the center to a point on the circle

we are given
center=(7,1)
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find the distance
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so the distance between point and center is radius
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radius is √37 units
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3 years ago
the 5th and 6th grade students at jackson middle school are going on a field trip. there are 6 classes in the fitth grade, and e
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2 years ago
Find the missing number in this function table.
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3 0
3 years ago
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Suppose that the rate of return on stocks is normally dis-tributed with mean of 9% and a standard deviation of 3%. If I pick fiv
alisha [4.7K]

Answer:

The probability that at least two stocks will have a return of more than 12% is 0.1810.

Step-by-step explanation:

Let <em>X</em> = rate of return on stocks.

The random variable <em>X</em> follows a Normal distribution, N (9, 3²).

Compute the probability that a stock has rate of return more than 12% as follows:

P(X\geq 12)=1-P(X

**Use the <em>z</em> table for the probability.

The probability of a stock having rate of return more than 12% is 0.1587.

Now define a random variable <em>Y</em> as the number of stocks that has rate of return more than 12%.

The sample size of stocks selected is, <em>n</em> = 5.

The random variable <em>Y </em>follows a Binomial distribution.

The probability of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...

Compute the value of P (X ≥ 2) as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{5\choose 0}(0.1587)^{0}(1-0.1587)^{5-0}-{5\choose 1}(0.1587)^{1}(1-0.1587)^{5-1}\\=1-0.4215-0.3975\\=0.1810

Thus, the probability that at least two stocks will have a return of more than 12% is 0.1810.

6 0
3 years ago
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