Answer:
Step-by-step explanation:
Given that there are six different toys and they are to be distributed to three different children.
The restraint here is each child gets atleast one toy.
Let us consider the situation as this.
Since each child has to get atleast one toy no of ways to distribute
any 3 toys to the three children each. This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways
So 3 toys to each one in 6x5x4 =120 ways
Now remaining 3 toys can be given to any child.
Hence remaining 3 toys can be distributed in 3x3x3 =27 ways
Total no of ways
= 120(27)
= 3240
The outlier is 84 and if you removed the outlier from the mean it would decrease.
•Given 7 - 8 = -1
• -[-7 + 8] = -1, This choice
• 0 - 7 + (-8) = -15
• 7? + -8 = -1, This choice (if I understand “07” correctly)
• -7 + 8 = 1
0.84% of the graduates will receive the tax break
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
Z = x - μ / σ
Z-scores are used to measure how far a measure is from the mean. We find the p-value associated with this Z-score by looking at the z-score table after finding the Z-score. The p-value represents the probability that the measure is smaller than X, which is the percentile of X. The probability of the measure being greater than X is calculated by subtracting 1 from the pvalue.
μ = $55,000 σ = $6,000
This is the pvalue of Z when X = $39,600. So
z = 39600 - 55000 / 6000
z = -2.5
z = -2.5 has a o value of 0.0084
0.84% of the graduates will receive the tax break.
To learn more about similar tax break:
brainly.com/question/15563518
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