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3 years ago

How to connect to my wireless printer for dummies?

1 answer:

8 0

It depends on the printers brand as there are a broad range of wireless printers offering all sorts of connections.

Generally speaking, you would want the printer to connect to the network (LAN) this could be done on the printer. Refer to the printer's manual. I think you can also connect it via the computer. Just find it on the computer on 'find printer' in your computers settings. Specify the printers name in order to this.

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Namecoin is an alternative blockchain technology that is used to implement decentralized version of Routing Banking System.A. Tr

vova2212 [387]

Answer:

False

Explanation:

Namecoin is a type of crypto currency which was originally pronged from Bitcoin software. It is coded in the fashion of Bitcoin with the same algorithm as well. Hence it is not a blockchain technology that is used to implement decentralized version of Routing Banking System. Namecoin can store data within its own blockchain transaction database.

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3 years ago

If you are trying move a hard drive from a non-working computer to a working computer for the purposes of accessing the data on

Llana [10]

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3 years ago

An alternative to configuring individual workstations is to establish configurations dynamically when the computers connect to t

Lapatulllka [165]

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Explanation:

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2 years ago

Question 16 (1 point)

Lana71 [14]

Answer:

C) the world wide web.

Explanation:

if you where to google the question it is the definition of the WWW

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3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago