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2 years ago

Find the area of the rhombus

Mathematics

1 answer:

Neporo4naja [7]2 years ago

7 0

Answer:

60 u²

Step-by-step explanation:

Finding second diagonal :-

d' = √{ 17² - 8²}
d' = √{ 289 - 64 }
d' = √{ 225 }
d' = 15 u

Using formula :-

A = 1/2 * d * d'
A = 1/2 * 15 * 8
A = 15 * 4 u²
A = 60 u²

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You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m

Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500 $\frac{N}{m}$

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

$mg y= \frac{1}{2} k x^{2}$

$mg(h +x) = \frac{1}{2} k x^{2}$

By rearranging the above equation we get

$k x^{2} - 2mgx - 2mg h = 0$

Put all the values in above equation we get

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By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0

2 years ago

Enter an equation in point-slope form for the line. Slope is 4 and (−3, −1) is on the line. The equation of the line in point sl

Licemer1 [7]

Answer:

y + 1 = 4 (x + 3)

Step-by-step explanation:

The formula is y - y1 = m (x - x1), so you put the variables in to y1 and x1 plus add the slope in as m, and there you are! Point slope form.

Hope this helps!

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2 years ago