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Alla [95]
3 years ago
14

Which expression is equivalent to 8-(6r+2) a -6r+6 b 2r+2 c 6r+10 d -6=10

Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

a -6r+6

Step-by-step explanation:

8-(6r+2)

Use - to expand the bracket

8-6r-2

Group like terms and simplify

-6r-2+8\\\\-6r+6

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Answer:

Step-by-step explanation:

I used calculus for this, as I'm not sure there's any other way to do it and to do it as easily. This is the volume of a solid found by using the disk method of rotation:

V=\pi\int\limits^a_b {[R(x)]^2-[r(x)]^2} \, dx

where R(x) is the outer shell of the solid and r(x) is the space inbetween the solid and the axis of rotation. There is no space between the solid and the axis of rotation, so r(x) = 0. R(x) is the height of the solid which is 3. Therefore, f(x) = 3 and that's the function we put into the formula with the lower bound of 3 and the upper bound of 5:

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6 0
2 years ago
Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are
o-na [289]

Answer:

<em>x=-7</em>

<em>y=11</em>

Step-by-step explanation:

<u>Perpendicular Vectors</u>

Two vectors defined as their endpoints \vec u= and \vec v= are perpendicular if their dot product a.b is zero. The dot product is

\vec u.\vec v=ac+bd

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector  

\overrightarrow{BC}==

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\overrightarrow{AB}==

this vector must be perpendicular to BC, so, applying the dot product we have

4(x-3)+40=0

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x=-7

The point D is D(17,y), we need to form a vector with C

\overrightarrow{CD}==

this vector must be perpendicular to BC, so, applying the dot product we have

(4)(10)+(10)(y-15)=0

40+10y-150=0

10y=110

y=11

The points are

\boxed{A(-7,9), D(17,11)}

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63 is the number you will substitute for x in the equation you've already written for part A.
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