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Irina18 [472]
3 years ago
8

He distance between Miami and Naples is 107 miles. The distance between Miami and Jacksonville is about three times this distanc

e. Landon estimates the distance between Miami and Jacksonville is about 400 miles. Is Landon's estimate reasonable? Why or why not?
Mathematics
1 answer:
zmey [24]3 years ago
4 0

Answer:

Step-by-step explanation:

Distance between Miami and Naples = 107 miles

Distance between Miami and Jacksonville is about three times this distance.

Distance between Miami and Jacksonville = 3 * 107 miles

= 321 miles

Landon estimates the distance between Miami and Jacksonville is about 400 miles

The estimate is too high

He should have estimated 107 miles to 110 miles which gives a total of 330 miles

Estimated 400 miles compared to 330 miles is too high

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Give an example of a rigid object
Ann [662]

– Examples: Smoke, Fire, Water, Wind, Leaves, Cloth, Magnets, Flocks, Fish, Insects, Crowds, etc

– Examples: Angry birds, Bodies tumbling, bouncing, moving around in a room and colliding, Explosions & Fracture, Drop the camera, etc…

Summarize rigid body simulation.

5 0
3 years ago
Read 2 more answers
A company is in the business of finding addresses of long-lost friends. The company claims to have a 70% success rate. Suppose t
Galina-37 [17]

Answer:

a) Figure attached

b) E(X) =\mu= np = 9*0.7=6.3

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

c) For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.7)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we can use the following R code:

> x <- seq(0,9,by = 1)

> y <- dbinom(x,9,0.7)

> plot(x,y,main="Histogram",type = "h")

And we can see on the figure attached the solution.

We see that the higher probabilities are from 4 to 9

Part b

The expected value is given by:

E(X) =\mu= np = 9*0.7=6.3

The variance is given by:

Var (X) =\sigma^2= np(1-p) = 9*0.7*(1-0.7)= 1.89

And the standard deviation is:

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

Part c

First we can find the probability that at least two addresses will be found in the list of 9 that we have like this:

P(X \geq 2)

We can use the complement rule and we have:

P(X \geq 2) = 1-P(X

We find the indicidual probabilities:

P(X=0)=(9C0)(0.7)^0 (1-0.7)^{9-0}=0.00001968

P(X=1)=(9C1)(0.7)^1 (1-0.7)^{9-1}=0.000413

P(X \geq 2) = 1-[0.00001968+0.000413]=0.9996

If we use the case of n=8 and we find P(X\leq 2), we got:

P(X \leq 2) = 0.9987

For the case n= 7

P(X \leq 2) = 0.9962

For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

5 0
3 years ago
T+20.04=14.3 uhm okay it says it's too short sooooo yea please answer
Goshia [24]
The answer is t=5.74
8 0
3 years ago
A function g is defined by g(x)=50−2x. If x increases by 7, by how much does g(x) decrease?
Temka [501]

Answer: g(x) decreases by 7

Step-by-step explanation:

Simple algebra and substitution of variables for the number can help you to solve the problem,

g(7)=50-2(7)

g(7)=50-14

g(7)=36

I hope this helps

8 0
3 years ago
Read 2 more answers
Please help! Question below
Marysya12 [62]
152... cuz 28 is perpendicular so... 180-28
5 0
4 years ago
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