Answer:
The expected number of seat belt wearing drivers among the five cars is 3.75, using the expected value of a binomial experiment.
Step-by-step explanation:
For each driver, there are only two possible outcomes. Either they wear their seatbelts, or they do not. This means that we solve this problem using concepts of the binomial probability distribution.
Binomial probability disitribution.
Probability of exactly x sucesses on n repeated trials, with p probability.
Has an expected value of:
.
(a) Describe how you would simulate the number of seat belt wearing drivers among the five cars.
You would simulate this number finding the expected value of the binomial experiment.
There are 5 cars, so .
75% of all drivers wear their seat belts, so .
So the expected number of seat belt wearing drivers among the five cars is:
The expected number of seat belt wearing drivers among the five cars is 3.75, using the expected value of a binomial experiment.
Answer:
a) 0.9523
b) 0.42
Step-by-step explanation:
Given:
husbands are watching television at prime time, P(H) = 0.80
husbands not watching television at prime time, P(H')= 1 - 0.80 = 0.20
When the husband is watching television, wife is also watching,
P( W | H ) = 0.50
When the husband is not watching television, wife is watching
⇒ P( W | H') = 0.10
Now,
a) The probability that wife is watching TV
⇒ P(W) = P( W | H')P(H') + P( W | H )P(H)
= (0.10 × 0.20) + (0.50 × 0.80)
= 0.02 + 0.4
= 0.42
By the Baye's theorem,
P( wife is watching television, when the husband is also watching tv)
⇒ P( H | W ) =
=
= 0.9523
b) P( wife is watching TV in prime time)
P(W) = P( W | H')P(H') + P( W | H )P(H)
= ( 0.10 × 0.20 ) + ( 0.50 × 0.80 )
= 0.02 + 0.4
= 0.42
9
2
+
6
+
^2 --- HOPE THIS HELPS :))
The most logical cause and effect or input and output relationship would be the number of pages in the assignment.
Thus depending on the number of pages present in a book, and assuming the person reads at an average rate, the number of pages and the rate allows us to determine the time taken.
X^2+2x^2=14+7
3x^2=21
x^2=7
x=±√7