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jolli1 [7]
3 years ago
9

Classifying a carbon atom by the number of carbons to which it is bonded can also be done in more complex molecules that contain

heteroatoms. classify each sp3 hybridized carbon atom in bilobalide, a compound isolated from ginkgo biloba extracts, as 1°, 2°, 3°, or 4°. be sure to answer all parts. 33 bilobalide

Chemistry
1 answer:
defon3 years ago
7 0

A sp³ hybridized carbon atom is the one which forms 4 single bonds with other atoms.

In the structure of Bilobalide, we can see 12 sp³ hybridized carbon atoms which are attached to other carbon, hydrogen and oxygen atoms.

In order to classify carbon atoms as 1°, 2°, 3°, or 4° we need to take a look at the atoms to which these carbon atoms are attached.

A 1° carbon atom is the one which is attached to only 1 carbon atom.

In the diagram, we can see 3 methyl groups ( -CH3) being attached to only 1 carbon atom. There is one more primary carbon atom.

There are 4 primary carbon atoms in Bilobalide.

A 2° carbon atom is the one which is attached to 2 other carbon atoms.

In Bilobalide we can see 4 secondary carbon atoms.

A 3° carbon atom is the one which is attached to 3 other carbon atoms.

In Bilobalide we can see only 1 tertiary carbon atom.

A 4° carbon atom is the one which is attached to 4 other carbon atoms.

In Bilobalide we can see 3 quaternary carbon atoms.

Please see the attached image for classification.

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Amino acids cannot be broken down to provide energy.
Ostrovityanka [42]
False, Dietary proteins are first broken down to individual amino acids by various enzymes and hydrochloric acid present in the gastro-intestinal tract. These amino acids are further broken down to α-keto acids which can be recycled in the body for generation of energy, and production of glucose or fat or other amino acids.
5 0
4 years ago
What is the value that corresponds to the number of atom
chubhunter [2.5K]

Answer:

6.022 x 10²³

Explanation:

Data Given:

mass of carbon = 12.01 g

individual particles = 6.02 x 10²³

number of atoms = ?

Solution:

Formula used to find the number of atoms

                no. of moles = number of atoms / 6.022 x 10²³ . . . . . (1)

So, first we have to find number of moles

Formula to find no. of moles

               no. of moles = mass in grams/ molar mass. . . . . (2)

molar mass of Carbon = 12.01 g/mol

Put values in eq.2

            no. of moles = 12.01 g / 12.01 g/mol

            no. of moles = 1 mol

Now put the values in eq. 1

                no. of moles = number of atoms / 6.022 x 10²³ . . . . . (1)

                    1 mol = number of atoms / 6.022 x 10²³

Rearrange the above equation

               number of atoms = 1 mol x 6.022 x 10²³

                number of atoms = 6.022 x 10²³

So it is 6.022 x 10²³ atoms in 12.01 grams of carbon. This 6.022 x 10²³ also Known as Avogadro's number that is one mole of any substance consists this number of atoms.

4 0
4 years ago
KOH (aq) + Fe(NO3)3 (aq) →
atroni [7]

Answer:

see below

Explanation:

1. Predicting products (double replacement): ab + cd ---> ad + cb

KNO₃(aq) + Fe(OH)₃(s)

2. balance the equation

3KOH (aq) + Fe(NO3)₃ (aq) ---> 3KNO₃(aq) + Fe(OH)₃(s)

3. I don't know if you need this but ionic equation: only aqueous things get split into ions; gas, liquid, and solids stay together

3K⁺(aq) + 3(OH)⁻(aq) + Fe³⁺(aq) + 3NO₃⁻(aq) ---> 3K ⁺(aq) + 3NO₃⁻(aq) + Fe(OH)₃(s)

removing things on both product and reactant side

3(OH)⁻(aq) + Fe³⁺(aq) --->Fe(OH)₃(s)

7 0
3 years ago
The names of monatomic anions are formed by replacing the ending of the name of the element with
ziro4ka [17]
The answer is - ide.

That is how you name the anions in a ionic compound, you replace the ending of the name of the element with ide.

Some examples:

Ionic compound            anion            name of the anion

NaCl                                Cl-                 chloride

KF                                    F-                  fluoride

NaI                                   I-                    iodide

CaBr2                              Br-                 bromide
5 0
4 years ago
ook at sample problem 18.12 in the 8th ed Silberberg book. Write a balanced chemical equation (salt hydrolysis). So acetate ion
vfiekz [6]

Answer:

Here's what I get  

Explanation:

1. Write the chemical equation

CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻; Kₐ = 2 × 10⁻⁵

Let's rewrite the equation as

A⁻ + H₂O ⇌ HA + OH⁻

2. Calculate Kb

K_{\text{b}} = \dfrac{K_{\text{w}}}{K_{\text{a}}} = \dfrac{1.00 \times 10^{-14}}{2 \times 10^{-5}} = 5 \times 10^{-10}

3. Set up an ICE table

                      A⁻ + H₂O ⇌ HA + OH⁻

I/mol·L⁻¹:      0.35                 0       0

C/mol·L⁻¹:       -x                  +x      +x

E/mol·L⁻¹:    0.35-x               x        x

4. Solve for x

\dfrac{\text{[HA ][OH$^{-}$]}}{\text{[A$^{-}$]}} = \dfrac{x^{2}}{0.35-x} = 5 \times 10^{-10}

Check for negligibility,

\dfrac{\text{[HA]}}{K_{\text{b}}} = \dfrac{0.35}{5 \times 10^{-10}} = 7 \times 10^{8}> 400\\\\\therefore x \ll 0.35\\\\\dfrac{x^{2}}{0.35} = 5 \times 10^{-10}\\\\x^{2} = 0.35 \times 5 \times 10^{-10} = 1.8\times 10^{-10}\\\\x = \sqrt{1.8\times 10^{-10}} = \mathbf{1 \times 10^{-5}}

5. Calculate the pOH

[OH⁻] = 1 × 10⁻⁵ mol·L⁻¹

pOH = -log[OH⁻] = -log(1 × 10⁻⁵) = 4.88

6. Calculate the pH.

pH + pOH = 14.00

pH + 4.88 = 14.00

pH = 9.12

Note: The answer differs from that given by Silberberg because you used only one significant figure for the Kₐ of acetic acid.

3 0
4 years ago
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