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Radda [10]
3 years ago
9

Alpha Decay

Chemistry
1 answer:
Inessa [10]3 years ago
4 0

Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.

<h3>What are the products of Uranium-238 and Thorium -228?</h3>

If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.

So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.

Learn more about isotope here: brainly.com/question/14220416

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\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{N}

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The unbalanced nuclear equation is

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

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\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{X}

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\rm _{6}^{15}\text{C} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{7}^{15}\text{N}

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