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allsm [11]
3 years ago
13

KOH (aq) + Fe(NO3)3 (aq) →

Chemistry
1 answer:
atroni [7]3 years ago
7 0

Answer:

see below

Explanation:

1. Predicting products (double replacement): ab + cd ---> ad + cb

KNO₃(aq) + Fe(OH)₃(s)

2. balance the equation

3KOH (aq) + Fe(NO3)₃ (aq) ---> 3KNO₃(aq) + Fe(OH)₃(s)

3. I don't know if you need this but ionic equation: only aqueous things get split into ions; gas, liquid, and solids stay together

3K⁺(aq) + 3(OH)⁻(aq) + Fe³⁺(aq) + 3NO₃⁻(aq) ---> 3K ⁺(aq) + 3NO₃⁻(aq) + Fe(OH)₃(s)

removing things on both product and reactant side

3(OH)⁻(aq) + Fe³⁺(aq) --->Fe(OH)₃(s)

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Crazy boy [7]

I am sorry can you explain it more?

3 0
3 years ago
The molar solubility of ag2s is 1.26 × 10-16 m in pure water. calculate the ksp for ag2s.
MAXImum [283]
Answer is: Ksp for silver sulfide is 8.00·10⁻⁴⁸.
Reaction of dissociation: Ag₂S(s) → 2Ag⁺(aq) + S²⁻(aq)<span>.
</span>s(Ag₂S) = s(S²⁻) = 1.26·10⁻¹⁶ M.
s(Ag⁺) = 2s(Ag₂S) = 2.52·10⁻¹⁶ M; equilibrium concentration of silver cations.
Ksp = s(Ag⁺)² · s(S²⁻).
Ksp = (2.52·10⁻¹⁶ M)² · 1.26·10⁻¹⁶ M.
Ksp = 6.35·10⁻³² M² · 1.26·10⁻¹⁶ M.
Ksp = 8.00·10⁻⁴⁸ M³.
6 0
3 years ago
What two elements are commonly found in Mica, Quartz and Feldspar? Explain your answer.
kifflom [539]

Answer:

oxygen and silicon, both are common

6 0
3 years ago
. The ring shape of the Cartwheel Galaxy is due to:
dlinn [17]

The ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

<h3>What causes the ring shape of the Cartwheel Galaxy?</h3>

The unusual shape of the Cartwheel Galaxy is due to a collision with a smaller galaxy. The recent star burst has lighted up the Cartwheel rim which has a diameter larger than that of the Milky Way galaxy in which our planet exists. The Cartwheel Galaxy is a lenticular ring galaxy which is about 500 million light-years away. This galaxy was discovered by Fritz Zwicky in the year 1941.

So we can conclude that the ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

Learn more about galaxy here: brainly.com/question/13956361

#SPJ1

7 0
1 year ago
The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i
antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC

c = specific heat capacity of gold = 0.1291joules/gram^oC

m = mass of gold =15.71 g

Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram

Heat gained by gold = 2093.0621 Joules + 997.585 Joules

=3090.6471 joules

6 0
3 years ago
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