We´re asked to determine the starting mass of KOH and H3PO4 based on the produced mass of K3PO4 and an unreacted amount of H3PO4.
The problem can be solved in 4 steps:
Step 1: Calculate the Molar Mass (MM) of KOH, H3PO4, and K3PO4.
Step 2: Calculate the moles of K3PO4, since we know the produced mass.
Answer:
6.30 M⁻¹s⁻¹.
Explanation:
As the reaction is first order with respect to a and b.
<em>The rate of the reaction = k [a][b],</em>
where, k is the rate constant of the reaction.
The rate of the reaction = 2.65 × 10⁻⁴ M/s,
[a] = 1.60 × 10⁻² M,
[b] = 2.67 × 10⁻³ M.
∴ k = (the rate of the reaction / [a][b]) = (2.65 × 10⁻⁴ M/s) / (1.60 × 10⁻² M)( 2.67 × 10⁻³ M) = 6.30 M⁻¹s⁻¹.
Answer:
P4 + 5O2 → P4O10
Explanation:
White Phosphorus - P4
Dioxygen - O2
Tetraphosphorus Decaoxide - P4O10
All atoms of the same element have the same number of protons.
