Question

What is the radical expression that is equivalent to the expression 27 1/5? Enter your answer as a radical. For example, if your answer is 25^1/4, enter your answer like this: cuberoot(14) CAN SOMEONE ANSWER FAST PLZ

Answer 1

Answer:

$\sqrt[5]{3^3}$

Step-by-step explanation:

Given: $27^{\frac{1}{5} }$

This is the fifth root. We need to write 5 in the index of the radical sign.

$\sqrt[n]{x} = x^\frac{1}{n}$

Here n is the index of the radical.

$27^{\frac{1}{5} } = \sqrt[5]{27}$

We can write 27 = 3*3*3 = $3^{3}$

$\sqrt[5]{27} = \sqrt[5]{3^3}$

Therefore, the answer is $27^{\frac{1}{5} } = \sqrt[5]{3^3}$

Answer 2

Answer:

$27^{\frac{1}{5} }=\sqrt[5]{3^3}$

Step-by-step explanation:

we are given

$27^{\frac{1}{5} }$

we can use rule to change exponent into radical

$\sqrt[n]{a} =a^{\frac{1}{n} }$

so, we can write as

$27^{\frac{1}{5}}=(3\times 3\times 3)^{\frac{1}{5}}$

$27^{\frac{1}{5}}=(3^3)^{\frac{1}{5}}$

now, we can use rule

and we can write our term as

$27^{\frac{1}{5} }=\sqrt[5]{3^3}$