Which of these improper fractions is between 4 and 5? How do I know. 13/3 13/4 13/5 13/6

Mathematics

2 answers:

FrozenT [24]2 years ago

7 0

13/3?

I think it is but so you put 13/3 into a proper fraction so 4 1/3

Masteriza [31]2 years ago

5 0

Answer:

13/3

Step-by-step explanation:

that would equal 4 1/3 the rest of them are over 5

You might be interested in

Write 15+45 as a product of two factors using the gcf and the distributive property

valkas [14]

Answer:

15(1 + 3)

Step-by-step explanation:

15 written in its prime factors is 3 × 5 (15 × 1)

45 written in its prime factors 3 × 3 × 5 (15 × 3)

The greatest common factor is 15: 15 × 1 = 15 and 15 × 3 is 45

∴ 15 + 45 = 15(1 + 3)

Hope this helps! Make me brainiest, lol it's fine if you don't. : )

5 0

2 years ago

Find the slope of the line passing through (-3, 4) and (1, -7) URGENT PLEASE HURRY

xeze [42]

Step-by-step explanation:

y=11x-5 or something like that.. I'm not sure on the ending

3 0

3 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$