I can't see nothing see nothing
Answer:
11
Step-by-step explanation:
The average rate of change of function f on interval [a, b] is ...
m = (f(b) -f(a))/(b -a)
Here, that is ...
m = (f(6) -f(2))/(6 -2)
So, we need to evaluate the function at x=6 and x=2. Writing it in "Horner form" makes this easier.
f(x) = (x +3)x -2
f(6) = (6 +3)6 -2 = 54 -2 = 52
f(2) = (2 +3)2 -2 = 10 -2 = 8
Then the slope is ...
m = (52 -8)/4 = 13 -2 = 11
The average rate of change of f(x) from 2 to 6 is 11.
Answer:
129.9 cm^2
Step-by-step explanation:
You can use the Law of Sines to find the hypotenuse. Because it's an equilateral triangle, it's the same value for the base. If you plug in the proper angles, being 90 degrees and 60 degrees because it's an equilateral triangle, the value of the base should be 17.32050808, or 17.32 if we're rounding. If you use the usual formula for finding the area of a triangle, b * h / 2 to get an answer of 129.9 cm^2. Hope this helps and isn't too confusing! There's a bunch of lessons on Khan Academy if you need more help!
This is a bit advanced for middle school, so we might be missing some information.
Answer:
hexagon
Step-by-step explanation:
It's a polygon with 6 sides, so it's a <em>hexagon</em>.
Answer:

Step-by-step explanation:
Consider the tetrahedron enclosed by the coordinate planes and the plane 2x + y + z = 2
Let A be the region obtained by projecting the volume(V) onto the xy-plane.
Similarly, the plane 2x + y + z = 2 intersects with the xy-plane in y = 2 - 2x.
Using the vertical strips, the region A is to the xy-plane can be expressed as:

Thus, the volume of the solid can be calculated as follows;


![V = \int^1_0 \bigg [2\times y -2x\times y - \dfrac{y^2}{2} \bigg]^{2-2x}_{0} \ dx \](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5E1_0%20%5Cbigg%20%5B2%5Ctimes%20y%20-2x%5Ctimes%20y%20-%20%5Cdfrac%7By%5E2%7D%7B2%7D%20%5Cbigg%5D%5E%7B2-2x%7D_%7B0%7D%20%5C%20dx%20%5C)
![V = \int^1_0 \bigg [2\times (2-2x) -2x\times (2-2x) - \dfrac{(2-2x)^2}{2} \bigg]\ dx](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5E1_0%20%5Cbigg%20%5B2%5Ctimes%20%282-2x%29%20-2x%5Ctimes%20%282-2x%29%20-%20%5Cdfrac%7B%282-2x%29%5E2%7D%7B2%7D%20%5Cbigg%5D%5C%20dx)
![V = \int^1_0 \bigg [2x^2-4x+2 \bigg]\ dx](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5E1_0%20%5Cbigg%20%5B2x%5E2-4x%2B2%20%5Cbigg%5D%5C%20dx)
![V = \bigg [2\dfrac{x^3}{3}-\dfrac{4x^2}{2}+2 x\bigg]^1_0](https://tex.z-dn.net/?f=V%20%3D%20%5Cbigg%20%5B2%5Cdfrac%7Bx%5E3%7D%7B3%7D-%5Cdfrac%7B4x%5E2%7D%7B2%7D%2B2%20x%5Cbigg%5D%5E1_0)
![V = \bigg [2\dfrac{(1)^3}{3}-\dfrac{4(1)^2}{2}+2 (1)-0\bigg]](https://tex.z-dn.net/?f=V%20%3D%20%5Cbigg%20%5B2%5Cdfrac%7B%281%29%5E3%7D%7B3%7D-%5Cdfrac%7B4%281%29%5E2%7D%7B2%7D%2B2%20%281%29-0%5Cbigg%5D)

