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aniked [119]
3 years ago
8

Help me please help me I really need help

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

44%

0.44 is 44% of 1.

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Solve the quadratic equation x2 - x = 30 by completing the square
kap26 [50]

Answer:

A

Step-by-step explanation:

Given

x² - x = 30

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- \frac{1}{2})x + \frac{1}{4} = 30 + \frac{1}{4}

(x - \frac{1}{2})² = \frac{121}{4}

Take the square root of both sides

x - \frac{1}{2} = ± \sqrt{\frac{121}{4} } = ± \frac{11}{2}

Add \frac{1}{2} to both sides

x = \frac{1}{2} ± \frac{11}{2}, thus

x = \frac{1}{2} - \frac{11}{2} = - 5

x = \frac{1}{2} + \frac{11}{2} = 6

5 0
3 years ago
In order to answer the question correctly, please use the following image below:
True [87]

Answer:

C = 2

Step-by-step explanation:

9c + 14 = 2c^2 + 9c + 6

-9c                     -9c

14 = 2c² + 6

-6           -6

8 = 2c²

4 = c²

c = 2

3 0
3 years ago
Read 2 more answers
"Parameterize the plane through the point (−1,−3,1) with the normal vector ⟨−4,4,3⟩
Makovka662 [10]
The equation of the required plane can be obtained thus:
-4(x + 1) + 4(y + 3) + 3(z - 1) = 0
-4x - 4 + 4y + 12 + 3z - 3 = 0
4x - 4y - 3z = 5

Let x = 1, y = 2, then 4(1) - 4(2) - 3z = 5
z = (4 - 8 - 5)/3 = -9/3 = -3
Thus, point (1, 2, -3) is a point on the plane.

Let a = (a1, a2, a3) and b = (b1, b2, b3) be vectors parallel to the plane.
Then, -4a1 + 4a2 + 3a3 = 0 and -4b1 + 4b2 + 3b3 = 0
Let a1 = 2, a2 = -1, then a3 = (4(2) - 4(-1))/3 = (8 + 4)/3 = 12/3 = 4 and let b1 = -1 and b2 = 2, then b3 = (4(-1) - 4(2))/3 = (-4 - 8)/3 = -12/3 = -4
Thus a = (2, -1, 4) and b = (-1, 2, -4)

Therefore, the required parametric equation is r(s, t) = s(2, -1, 4) + t(-1, 2, -4) + (1, 2, -3) = (2s, -s, 4s) + (-t, 2t, -4t) + (1, 2, -3) = (2s - t + 1, -s + 2t + 2, 4s - 4t - 3)


3 0
4 years ago
Assume the heights in a female population are normally distributed with mean 65.7 inches and standard deviation 3.2 inches. Then
siniylev [52]

Answer:

0.620

Step-by-step explanation:

We know that 1 feet = 12 inches, so, 5 feet is equivalent to 60 inches. Then, we are looking for the probability that a typical female from this population is between 60 inches and 67 inches. We know that

\mu = 65.7 inches and

\sigma = 3.2 inches

and the normal density function for this mean and standard deviation is

\frac{1}{\sqrt{2\pi } 3.2}exp[-\frac{(x-65.7)^{2}}{2(3.2)^{2}} ]

The probability we are looking for is given by

\int\limits^{67}_{60} {\frac{1}{\sqrt{2\pi } 3.2}exp[-\frac{(x-65.7)^{2}}{2(3.2)^{2}} ] } \, dx =0.620

You can use a computer to calculate this integral. You can use the following instruction in the R statistical programming language

pnorm(67, 65.7, 3.2)-pnorm(60, 65.7, 3.2)

7 0
3 years ago
Cynthia walk 9/100 Miles to school and 3/10 Miles friends house how many miles does Cynthia walk total
aleksklad [387]

Answer:

12 Miles

Step-by-step explanation:

6 0
2 years ago
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