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3 years ago

For an independent-measures anova comparing four treatment conditions, dfbetween = 3.

1 answer:

3 0

For an independent-measures anova comparing four treatment conditions, dfbetween = 3.

TRUE.

The dfbetween is given by the number of treatments minus 1.

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medical tests. Task Compute the requested probabilities using the contingency table. A group of 7500 individuals take part in a

uysha [10]

Probabilities are used to determine the chances of an event

The probability that a person is sick is: 0.008
The probability that a test is positive, given that the person is sick is 0.9833
The probability that a test is negative, given that the person is not sick is: 0.9899
The probability that a person is sick, given that the test is positive is: 0.4403
The probability that a person is not sick, given that the test is negative is: 0.9998
A 99% accurate test is a correct test

(a) Probability that a person is sick

From the table, we have:

$\mathbf{Sick = 59+1 = 60}$

So, the probability that a person is sick is:

$\mathbf{Pr = \frac{Sick}{Total}}$

This gives

$\mathbf{Pr = \frac{60}{7500}}$

$\mathbf{Pr = 0.008}$

The probability that a person is sick is: 0.008

(b) Probability that a test is positive, given that the person is sick

From the table, we have:

$\mathbf{Positive\ and\ Sick=59}$

So, the probability that a test is positive, given that the person is sick is:

$\mathbf{Pr = \frac{Positive\ and\ Sick}{Sick}}$

This gives

$\mathbf{Pr = \frac{59}{60}}$

$\mathbf{Pr = 0.9833}$

The probability that a test is positive, given that the person is sick is 0.9833

(c) Probability that a test is negative, given that the person is not sick

From the table, we have:

$\mathbf{Negative\ and\ Not\ Sick=7365}$

$\mathbf{Not\ Sick = 75 + 7365 = 7440}$

So, the probability that a test is negative, given that the person is not sick is:

$\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Not\ Sick}}$

This gives

$\mathbf{Pr = \frac{7365}{7440}}$

$\mathbf{Pr = 0.9899}$

The probability that a test is negative, given that the person is not sick is: 0.9899

(d) Probability that a person is sick, given that the test is positive

From the table, we have:

$\mathbf{Positive\ and\ Sick=59}$

$\mathbf{Positive=59 + 75 = 134}$

So, the probability that a person is sick, given that the test is positive is:

$\mathbf{Pr = \frac{Positive\ and\ Sick}{Positive}}$

This gives

$\mathbf{Pr = \frac{59}{134}}$

$\mathbf{Pr = 0.4403}$

The probability that a person is sick, given that the test is positive is: 0.4403

(e) Probability that a person is not sick, given that the test is negative

From the table, we have:

$\mathbf{Negative\ and\ Not\ Sick=7365}$

$\mathbf{Negative = 1+ 7365 = 7366}$

So, the probability that a person is not sick, given that the test is negative is:

$\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Negative}}$

This gives

$\mathbf{Pr = \frac{7365}{7366}}$

$\mathbf{Pr = 0.9998}$

The probability that a person is not sick, given that the test is negative is: 0.9998

(f) When a test is 99% accurate

The accuracy of test is the measure of its sensitivity, prevalence and specificity.

So, when a test is said to be 99% accurate, it means that the test is correct, and the result is usable; irrespective of whether the result is positive or negative.

Read more about probabilities at:

brainly.com/question/11234923

4 0

3 years ago

Solve the inequality 2x−y⩾−5 for y. Which inequality represents the inequality in slope-intercept form?

aleksandr82 [10.1K]

Answer:

$y\leq 2x+5$

This represents slope intercept form: y = mx + b

Step-by-step explanation:

$2x - y \geq -5\\2x+5\geq y$

4 0

3 years ago

Select the locations on the number line to plot the points 4 1/ 3 and −1 1/3 .

Olin [163]

We have that
4 1/ 3
−1 1/3 
the answer in the attached figure

3 0

3 years ago

Read 2 more answers

HELPPP MEEE PLEASEEEEE

meriva

Answer:

A' (4, -3)

Step-by-step explanation:

Since it's a reflection over the x-axis, the point would undergo the following rigid transformation:

(x, y) --> (x, -y)

so,

(4, 3) --> (4, -3)

3 0

3 years ago

Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other

Vikentia [17]

Answer:

the buses are at 50 mph and 60 mph

the distance = 210 miles

Step-by-step explanation:

r1 = rate of bus 1

r2 = rate of bus 2

r1 = r2+10 (The speed of one of the buses was 10 mph greater than the speed of the other bus.)

distance = rate * time

for bus 1

distance = r1 * (3.5)

bus 2 was 1/6 short of making it to town b

so it made it 5/6 of the way

5/6 distance = r2 * (3.5)

multiply by 6/5 on each side

distance = 6/5 * r2 * 3.5

set the distances equal

r1 * (3.5)=6/5 * r2 * 3.5

r1 = 6/5 * r2

now set rate 1 equal (r1 = r2+10)

6/5 * r2 = r2 + 10

solve for r2 by subtracting r2 on each side

6/5 r2 -r2 = 10

6/5 = 1.2

1.2 r2 - r2 =10

.2 r2 = 10

divide by .2 on each side

r2 = 10/.2

r2 = 50

r1 = 50 + 10

r1 =60

to find the distance

distance = r1 * (3.5)

distance = 60 * 3.5

distance = 210 miles

3 0

3 years ago

Read 2 more answers