Answer:
Step-by-step explanation:
Given that :
μ1 = 39420 ; σ1 = 1659 ; s1 = 12
μ2 = 30215 ; σ2 = 4116 ; s2 = 26
df1 = 12 - 1 = 11
df2 = 26 - 1 = 25
98 % confidence interval of the difference in sample means :
Pooled Variance :
S²p = ((df1 * s1²) + (df2 * s2²)) / (df1 + df2)
((11×1659^2)+(25×4116^2))÷(11+25) = 12605874.75
Standard Error :
√(S²p/n1) + (S²p/n2)
√(12605874.75/12) + (12605874.75/26)
= 1239.0847
Answer:
Part A: 9.75x > 195
Part B: x > 20
Step-by-step explanation:
Let's say Mark works for x hours. For each hour he works, 9.75 dollars are added to Mark's salary. Therefore, for 1 hour, he gets $9.75, for 2 hours, he gets $9.75 + $9.75 = $9.75 * 2 = $19.50, and for x hours, he gets $9.75 * x as his salary.
We want his salary to be more than $195, so we have $9.75 * x (his salary) > $195, which can be written as 9.75x > 195
divide both sides by 9.75 to solve for x
x > 20
Answer: I do not know sorry
Step-by-step explanation:
Answer:
-1/3
Step-by-step explanation:
Step-by-step explanation:
slope = 2-4/2-1 = -2
y - 2 = -2(x - 2)
y-2 = -2x +4
y = -2x + 6