Answer:
x-coordinates of relative extrema = 
x-coordinates of the inflexion points are 0, 1
Step-by-step explanation:

Differentiate with respect to x


Differentiate f'(x) with respect to x

At x =
,

We know that if
then x = a is a point of minima.
So,
is a point of minima.
For inflexion points:
Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.
So, x-coordinates of the inflexion points are 0, 1
All you have to do is divide 38 divided by 5 which = 7 r 3
I hope this helps.
Have a awesome day. :)
The cube root of 60 is 3.87 approximately.
Step by step solution:
We can calculate the cube root by Halley's method:
The formula is ![\sqrt[3]{a} = x ((x^{3} + 2a)/(2x^{3} + a))](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%20%3D%20x%20%28%28x%5E%7B3%7D%20%20%2B%202a%29%2F%282x%5E%7B3%7D%20%20%2B%20a%29%29)
where,
a = number whose cube root is being calculated
x = integer guess of its cube root.
Here a = 60,
Suppose x as 3
[∵ 3³ = 27 and 27 is the nearest perfect cube that is less than 60]
⇒ x = 3
Therefore,
∛60 = 3 (3³ + 2 × 60)/(2 × 3³ + 60)) = 3.87
⇒ ∛60 ≈ 3.87
Therefore, the cube root of 60 is 3.87 approximately.
Here , ∛60 is irrational because it cannot be expressed in the form of p/q where q ≠ 0.
Therefore, the value of the cube root of 60 is an irrational number.
Learn more about cube root :brainly.com/question/27863878
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Answer:
No. The answer is 72
Step-by-step explanation:
As 12x6=72