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3 years ago

Charlie puts $50000 in a stock account, but it loses money at a rate of 20%

Mathematics

1 answer:

Alina [70]3 years ago

4 0

Answer:

You dind't include the answer choices but it should look something like

$50000(.8)^t$

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Profit P(x), is the difference between revenue, R(x), and cost, C(x), so P(x)=R(x)-C(x). Which expression represents P(x), if R(

siniylev [52]

Answer:

P(x)= x ^4-3x^3+x^2-4

Step-by-step explanation:

Given data

R(x) = 2x ^4-3x^3+2x-1

c(x)=x^4-x^2+2x+3

We know that

P(x)=R(x)-C(x)

Hence

P(x)= 2x ^4-3x^3+2x-1-(x^4-x^2+2x+3)

open bracket

P(x)= 2x ^4-3x^3+2x-1-x^4+x^2-2x-3

Collect like terms

P(x)= 2x ^4-x^4-3x^3+x^2-2x+2x-3-1

P(x)= x ^4-3x^3+x^2-4

4 0

3 years ago

Consider the initial value function y given by

Nuetrik [128]

Answer:

y(s) = $\frac{5s-53}{s^{2} - 10s + 26}$

we will compare the denominator to the form $(s-a)^{2} +\beta ^{2}$

$s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$

comparing coefficients of terms in s

$s^{2} :$ 1

s: -2a = -10

a = -2/-10

a = 1/5

constant: $a^{2}+\beta ^{2} = 26$

$(\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09$

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = $A(s-a)+B((s-a)^{2} +\beta ^{2} )$

we insert the values of a and β

$\\5s-53$ = $A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )$

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

the constants are

a = 0.2

β = 5.09

A = 5.4

B = -2

Step-by-step explanation:

since the denominator has a complex root we compare with the standard form $s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$
Expand and compare coefficients to obtain the values of a and β as shown above
substitute the values gotten into the function
Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0

3 years ago

Which expression haves the same value as 59.2- 84.7

Radda [10]

- 84.7 + 59.2, this is your expression

3 0

3 years ago

What is the product?

makkiz [27]

Step-by-step explanation:

(4s + 2) × (5s² + 10s +3)

we know immediately the first and the last term of the result, because there is only one operation to build them :

20s³ and 6.

so, the first answer option is already eliminated.

let's multiply

4s×5s² + 4s×10s + 4×3s + 10s² + 20s + 6

20s³ + 40s² + 12s + 10s² + 20s + 6

20s³ + 50s² + 32s + 6

so, the last answer option is correct.

4 0

2 years ago

Given PA=13 in. and CB=15 in. What is CA ?

alexandr1967 [171]

Triangles CPA and CPB are both right triangles. They share a leg, so that leg in one triangle is congruent to that leg in the other triangle. We are given that PA is congruent to PB by the hash marks on the diagram. Thus two legs and an included angle are congruent between the triangles.

... ∆CPA ≅ ∆CPB by the SAS postulate

Then side CA ≅ CB = 15 in, because corresponding parts of congruent triangles are congruent (CPCTC).

... CA is 15 in.

8 0

3 years ago

Read 2 more answers