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larisa86 [58]
3 years ago
12

Given: m || n , <1 is congruent to <3 Prove: p || q

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

A= Angle 1 congruent to angle 2

B= Transitive Property

C= Converse Corresponding angles theorem

Step-by-step explanation:

prisoha [69]3 years ago
3 0
I would need see what your choices are to give exact answers, but I think the main idea here is to see that angles 1 and 3 are the same, and since the alternate interior angle theorem states parallel lines through a line, or another set of parallel lines, form equal angles on those positions, the lines that form those angles, p and q, must be parallel.
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The figure shows a triangle with an angle bisector. If angle SUT= 34°, find the measurement of angle 1?
Burka [1]

The ANGLE BISECTOR mentioned in the problem is simply just a line that separates an angle in half.

Meaning if it bisects ∠SUT which is 34. It just means that it divides the angle 34 into 2 equal parts.

Therefore ∠1 is just one-half of the ∠SUT.

\begin{gathered} m\angle1=\frac{\angle SUT}{2} \\ m\angle1=\frac{34}{2} \\ m\angle1=17 \end{gathered}

Therefore the measurement of ∠1 is 17°.

8 0
1 year ago
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
4 years ago
Find the measure of the exterior angles of the following regular polygons: a triangle, a quadrilateral, a pentagon, an octagon,
musickatia [10]

Answer:

Triangle: 120

Quadrilateral: 90

Pentagon: 72

Octagon: 45

Decagon: 36

30-gon: 10

50-gon: 7.2

100-gon: 3.6

Step-by-step explanation:

360/n = the measure on the exterior angle

n = the number of sides

6 0
3 years ago
Which group of numbers are all prime?
Nana76 [90]
C

This is because none of the numbers can be divided by any number other than themselves or 1.
5 0
3 years ago
Choose the correct proportions.<br><br> 4, 1, 2, 2<br><br> a) 1:2 = 2:4<br> b) 1:4 = 2:2
Grace [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
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