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larisa86 [58]
3 years ago
12

Given: m || n , <1 is congruent to <3 Prove: p || q

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

A= Angle 1 congruent to angle 2

B= Transitive Property

C= Converse Corresponding angles theorem

Step-by-step explanation:

prisoha [69]3 years ago
3 0
I would need see what your choices are to give exact answers, but I think the main idea here is to see that angles 1 and 3 are the same, and since the alternate interior angle theorem states parallel lines through a line, or another set of parallel lines, form equal angles on those positions, the lines that form those angles, p and q, must be parallel.
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The Angels won ten games out of sixteen of their games during the 2009 regular season. At this rate, how many games do they need
Alexus [3.1K]

Answer: 80

10/16=0.625

0.625x80=50

4 0
3 years ago
If a temperature in degrees Celsius this is given as C finding the sum of 1.8 timesC and 33 gives the temperature in degrees Fah
aleksley [76]
Alright well first off, converting Celsius to Fahrenheit is 1.8c+32. converting Fahrenheit to Celsius is 5(f-32)/9.
the temperature in Fahrenheit is given by °f.
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3 years ago
Which of these equations have no solution? Check all that apply.
Murljashka [212]

Answer:

B and E

Step-by-step explanation:

(26x+2)+2=2(x+3)+1 - solution = 1/8

2x+3(x+5)=5(x-3) - NO SOLUTION

4x+3=x+12 - solution = 3

4 - (2x + 5) = {(-4x - 2) - solution = -1/2

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3 0
3 years ago
Evaluate: 17 – 5(–3)<br> A.–28<br> B. 32<br> C. –8<br> D.–21
trapecia [35]
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8 0
3 years ago
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
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