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vovikov84 [41]
3 years ago
14

QUESTION 4

Chemistry
1 answer:
Yuri [45]3 years ago
3 0

Answer:

bhejejenennejdjendkw

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Which of the following is the general definition of a gas?
MrRissso [65]
Choice 2 possibly, not positive
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4 years ago
In a heat engine of 1000 j of heat enters the system and the piston does 500 j of work what is the final internal energy of the
muminat

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

\Delta U=q+w\\\\U_{final}-U_{initial}=q+w

where,

U_{final} = final internal energy

U_{initial} = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and U_{initial}

initial internal energy = U_{initial} = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

U_{final}-(2000J)=(1000J)+(500J)

(4) By solving the terms, we get

U_{final}-(2000J)=(1000J)+(500J)

U_{final}-(2000J)=1500J

U_{final}=2000J+1500J

U_{final}=3500J

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

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Plant cell synthesize energy rich organic molecules and later energy is released through the processes of
zmey [24]
Pretty sure its photosynthesis ?

7 0
3 years ago
What subatomic particle(s) is on the outside of the atom?
asambeis [7]

Answer:

electrons

Explanation:

protons and neutrons are found in the nucleus while electrons are outside the nucleus

4 0
4 years ago
The amount of heat (q) gained or lost by a substance (with mass m) as its temperature changes (ΔT) depends on its specific heat
wariber [46]

Answer:

As the specific heat capacity for pure diamond is 0.5091\frac{J}{g.K} and it is different from the specific heat capacity found that is 0.2699\frac{J}{g.K}, the diamond sample is not pure.

Explanation:

1. As the problem says the equation that describes the amount of heat gained or lost by a substance is:

q=Cp*m*(T_{2}-T_{1})

q=Cp*m*ΔT

where q is the amount of heat, Cp is the specific heat capacity, m is the mass and ΔT is the change in the temperature.

2. Solving for specific heat capacity:

Cp=\frac{q}{m*(T_{2}-T_{1})}

3. Replacing values:

Cp=\frac{26.21J}{2.03g*(73.81C-25.99C}

Cp=0.2699\frac{J}{g.K}

As the specific heat capacity for pure diamond is 0.5091\frac{J}{g.K} and it is different from the specific heat capacity found that is 0.2699\frac{J}{g.K}, the diamond sample is not pure.

3 0
3 years ago
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