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3 years ago

How many molecules are there in 24 grams of FeF(3)?

Chemistry

1 answer:

Burka [1]3 years ago

5 0

The SAME number of molecules are in ANY “mole” of a compound or element. So, you only need to ... 24 g116 g/mol=0.207 moles of FeF3.

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Calculate the volume of a 0.5M solution containing 20g of NaOH

Tju [1.3M]

Answer:

Explanation:

First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:

Mass = 20g

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Number of mole =?

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 20/40 = 0.5mol

From the question given, we obtained the following data:

Molarity = 0.5M

Mole = 0.5mole

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.5/0.5

Volume = 1L

6 0

3 years ago

Read 2 more answers

Which pair of elements would most likely form a covalent bond

denpristay [2]

Answer:

Nonmetals and nonmetals tend to form covalent bonds.

P and S

Explanation:

5 0

2 years ago

Waves transport water in the deep ocean toward the coastlines. True or false

ASHA 777 [7]

Answer:

Most likely true

Explanation:

because the speed of all ocean waves is controlled by gravity, wavelength, and water depth. ... Waves moving through water deeper than half their wavelength are known as deep-water waves. On the other hand, the orbits of water molecules in waves moving through shallow water are flattened by the proximity of the sea surface bottom.

7 0

3 years ago

A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis

Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

$P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa$

The factor will the volume of the diver's lungs change upon arrival at the surface:

$\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4$

5 0

3 years ago

According to the following reaction, how many grams of ammonia will be formed upon the complete reaction of 31.2 grams of hydrog

Aneli [31]

Answer:

176.8 g of ammonia, NH3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the mass of H2 that reacted and the mass of NH3 produced from the balanced equation. This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6 g

Molar mass of NH3 = 14 + (3x1) = 17 g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34 g.

From the balanced equation above,

6 g of H2 reacted to produce 34 g of NH3.

Finally, we shall determine the mass of ammonia, NH3 produced by reacting 31.2 g of H2.

This can be obtained as follow:

From the balanced equation above,

6 g of H2 reacted to produce 34 g of NH3.

Therefore, 31.2 g of H2 will react to produce = (31.2 x 34)/6 = 176.8 g of NH3.

Therefore, 176.8 g of ammonia, NH3 were obtained from the reaction.

8 0

3 years ago