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cricket20 [7]
3 years ago
15

In both nuclear fission and nuclear fusion reactions, energy is converted to mass.

Chemistry
2 answers:
mr_godi [17]3 years ago
8 0
That is false. mass is converted into energy
juin [17]3 years ago
5 0
False, the energy is released .
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How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of formula units of Sr(HCO_3)_2=4.55\times 10^{15}

As, 6.022\times 10^{23}  number of formula units are contained in 1 mole of a substance.

So, 4.55\times 10^{15} number of formula units will be contained in = \frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

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3 years ago
Calculate the volume in mL of a 0.708 M KOH solution containing 0.098 mol of solute
Olenka [21]
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For every liter there is 1000 mL:
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7 0
3 years ago
Why does burned toast taste so bad? Is it a chemical or physical change?
german

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4 0
2 years ago
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After a 4.626g sample of silver oxide is heated, 4.306g of silver metal remains. What is the empirical formula of the compound?
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Answer:

The empirical formula is Ag2O.

The empirical formula is Ag2O.Explanation:

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to 2O.

do the steps ...

To get this into an integer ratio, we divide both numbers by the smaller value.

From this point on, I like to summarize the calculations in a table.

ElementAgMass/gXMolesXllRatiomllIntegers

—————————————————−———mAgXXXm7.96Xm0.07377Xll2.00mmm2

mlOXXXXl0.59mm0.0369Xml1mmmml1

There are 2 mol of Ag for 1 mol of O.

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2 years ago
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