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4 years ago

In both nuclear fission and nuclear fusion reactions, energy is converted to mass.

Chemistry

2 answers:

mr_godi [17]4 years ago

8 0

That is false. mass is converted into energy

juin [17]4 years ago

5 0

False, the energy is released .
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How many atoms are in 1.14 mol of sulfur trioxide

yawa3891 [41]

2.75 x 10^24

Hope this helped :)

8 0

4 years ago

0.5 gm of mixture of NH4Cl and NaCl was boiled with 25 ml of 0.95 N NaOH in a vessel till all the ammonia is expelled.The residu

GalinKa [24]

Answer:

72.66%

Explanation:

NH₄Cl reacts in presence of NaOH producing ammonia, NH₃, as follows:

NH₄Cl + NaOH → NaCl + NH₃ + H₂O

The residual NaOH reacts with H₂SO₄ as follows:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.

The equivalent-gram of H₂SO₄ are:

16mL * 0.1N * 1.06 = 1.696mEq.

As the complete residual solution is 100mL but the neutralization was made only with 10mL, the mEq you need to neutralize the residual NaOH is:

1.696mEq * (100mL / 10mL) = 16.96mEq.

The mEq of NaOH you add in the first are:

25mL * 0.95mEq = 23.75mEq

That means the NaOH that reacts = moles of NH₄Cl is:

23.75mEq - 16.96mEq = 6.79mEq = 6.79mmoles NH₄Cl =

6.79x10⁻³ moles NH₄Cl

In grams (Using molar mass NH₄Cl = 53.5g/mol):

6.79x10⁻³ moles NH₄Cl * (53.5g / mol) =

0.3633g of NH₄Cl are in the original mixture.

% is:

0.3633g/ 0.5g * 100 = 72.66%

8 0

3 years ago

How are continental drift and plate tectonics related

lozanna [386]

The continental drift is what caused plate tectonics

5 0

3 years ago

For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:

Agata [3.3K]

Answer : The moles of $NH_3$ formed are, 22.3 moles.

Explanation : Given,

Moles of $N_2H_4$ = 16.72 mol

The given chemical reaction is:

$3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)$

From the balanced chemical reaction, we conclude that:

As, 3 moles of $N_2H_4$ react to give 4 moles of $NH_3$

So, 16.72 moles of $N_2H_4$ react to give $\frac{4}{3}\times 16.72=22.3$ moles of $NH_3$

Therefore, the moles of $NH_3$ formed are, 22.3 moles.

8 0

4 years ago

You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?

umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

$N=\frac{eq_{solute}}{V_{solution}}$

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

$eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq$

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

$m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4$

Best regards.

4 0

3 years ago