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navik [9.2K]
3 years ago
13

Can someone please help me with 5 and 6(Best answer = Brainliest)

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0
5. 
First plug the value of x into the equation
 2(-2y-12)+y=9
then solve for y
2(-2y)+2(-12)+y=9 \\ -4y+(-24)+y=9 \\ -4y-24+y=9 \\ -3y-24=9 \\ -3y=33 \\ \frac{-3y}{-3}= \frac{33}{-3} \\ y = -11

6. Do the same steps 
5(-y-1)+y=-13 \\ 5(-y)+5(-1)+y=13 \\ -5y+(-5)+y=13 \\ -5y-5+y=13 \\ -4y-5=13 \\ -4y=18 \\ \frac{-4y}{-4}= \frac{18}{-4} \\ y=-4.5 

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A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108
Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

4x+L=108

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

V=x^2L

If we express L in function of x using the restriction equation, we get:

4x+L=108\\\\L=108-4x

We replace L in the volume formula and we get

V=x^2L=x^2*(108-4x)=-4x^3+108x^2

To maximize the volume we derive and equal to 0

\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18

We can replace x to calculate L:

L=108-4x=108-4*18=108-72=36

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

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3 years ago
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Ira Lisetskai [31]

Answer:

JL = 78

Step-by-step explanation:

MN is a midsegment. Based on the midsegment theorem,

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MN = 5x - 16

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Plug in the value

5x - 16 = ½(4x + 34)

5x - 16 = ½*4x + ½*34

5x - 16 = 2x + 17

Collect like terms

5x - 2x = 16 + 17

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✔️JL = 4x + 34

Plug in the value of x

JL = 4(11) + 34

JL = 44 + 34

JL = 78

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Area=2.5

Step-by-step explanation:

area

area = length \times width

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