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3 years ago

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Which point is a solution to y>-3x +6? a. (0,6)b. (1,-2)C. (1,2) d. (4,5)

1 answer:

Klio2033 [76]3 years ago

8 0

Answer:

actually i dont know either im trying to find that out

Step-by-step explanation:

i dont get it

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Unit 4 Test, Part 2: Congruence and Constructions<br> Help with my math please

lakkis [162]

Answer/Step-by-sep explanation:

1. Given:

∆NMK ≅ ∆TRP

$\overline{NM} = 20$

$\overline{MK} = 15$

$\overline{KN} = 25$

$\overline{TR} = 3x - 1$

a. To complete the congruent statement, thus: ∆MNK ≅ ∆RTP

b. The side that is congruent to $\overline{TR}$ is $\overline{NM}$ . Thus:

$\overline{TR}$ ≅ $\overline{NM}$

c. Since $\overline{TR}$ ≅ $\overline{NM}$ , therefore:

$\overline{TR} = \overline{NM}$

$3x - 1 = 20$ (substitution)

Add 1 to both sides

$3x = 20 + 1$

$3x = 21$

Divide both sides by 3

$x = \frac{21}{3}$

$x = 7$

2. a. Slope of LK = $\frac{rise}{run} = \frac{4}{3}$

Slope of LM = $\frac{rise}{run} = -\frac{3}{5}$

b. ✍️Length of LK is the distance between L(-7, 4) and (-4, 8):

$Lk = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$Lk = \sqrt{(-4 -(-7))^2 + (8 - 4)^2}$

$Lk = \sqrt{(3)^2 + (4)^2}$

$Lk = \sqrt{9 + 16}$

$Lk = \sqrt{25}$

$Lk = 5$

✍️Length of LM is the distance between L(-7, 4) and (-2, 1):

$LM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$LM = \sqrt{(-2 -(-7))^2 + (1 - 4)^2}$

$LM = \sqrt{(5)^2 + (-3)^2}$

$LM = \sqrt{25 + 9}$

$LM = \sqrt{34}$

$LM = 5.8$ (nearest tenth)

∆KLM is not an isosceles ∆ because it does not has two equal side lengths. This we can see because LK and LM are not equal.

Therefore, Anthony is incorrect. Am isosceles ∆ has two equal sides.

8 0

3 years ago

Need help plz plz thx

Vera_Pavlovna [14]

The answer is D. To solve 3/5 ÷ 4/7 you would change it to 3/5 × 7/4.

5 0

4 years ago

Write the prime factorization for 168

11Alexandr11 [23.1K]

$168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7$

7 0

4 years ago

What is the solution to the system of equations 2x-y=7 and y=2x+3

Yuri [45]

Make y the subject in both equations

$2x-y=7$

$-y=-2x+7$

$y=2x-7$

For the second equation

$y=2x+3$

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

$NO SOLUTION$

The correct answer is C

6 0

3 years ago

LCM of 4/6 and 4/8????

Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0

2 years ago