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3 years ago

Which is an asymptotic of the graph of the function y=cot [x- 2pi/3]

Mathematics

1 answer:

astraxan [27]3 years ago

5 0

Answer:

Step-by-step sexplanations

yourmomhot

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A company makes a standard model flashlight (s) and a delux flashlight (d) the company makes 3$ profit on each standard model an

garri49 [273]

Answer:

your answer should be B

Step-by-step explanation:

4 0

3 years ago

If your good in math please help me

Feliz [49]

Answer:

350.82

Step-by-step explanation:

To find the surface area, you must add up all of the areas of each shape of the prism in order to get the sum surface area.

The rectangle's area ( $lw$ ):

$7.21*14=100.94$

The triangle's area ( $\frac{1}{2}bh$ ):

$\frac{1}{2} (6)(8)$

$\frac{1}{2} (48)=24$

Now add up all the sides. (3 Rectangles, 2 Triangles.)

$100.94 + 100.94 + 100.94 + 24 + 24$

$=350.82$

The total surface area is 350.82 cm squared.

6 0

3 years ago

find the value of cos theta, if sin theta= 1/2; 0 degrees greater than or equal to theta < 90 degrees

vagabundo [1.1K]

Answer:

Step-by-step explanation:

According to the ratios table, if

sin theta = 1/2

Then theta = 30°

Cos theta = cos 30° =root 3 /2

6 0

3 years ago

Read 2 more answers

Please help!!<br> i will mark as brainliest

Viktor [21]

Step-by-step explanation:

okay

I think you should use the method of tan 30

and then find x by using pythagorean theorem

4 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

2 years ago