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3 years ago

What is the sum of 6 feet 10 inches and 8 feet 9 inches?

2 answers:

7 0

B. 15ft. 7in.

Add the smaller measurement first, which in this case is inches. So you should have 19in. Then add feet, 14ft. Currently we have 14ft and 19in. But 19in can be simplified, since 12in is one foot. So take one foot out of 19 in and you have 7inches left. Add that one to 14. And in the end you should have 15ft and 7in.

vivado [14]3 years ago

6 0

Lets first convert everything to inches.

6 feet= 12*6 = 72 + 10 = 82 inches
8 feet= 12*8 = 96+9 = 105 inches

Now add!

82+105 = 187

Now convert them back to feet.

187/12 = 15 feet

12*15 = 180

187 - 180 = 7 inches

15 feet. 7 inches.

Final answer: B. 15 ft. 7 in.

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Account (A) is a saving account , the interest earned after 1 year is $12 .If the interest rate is 3.2% for account (A). How muc

BaLLatris [955]

Answer:

The principal for the account is $375.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

The interest earned after 1 year is $12 .If the interest rate is 3.2% for account (A).

This means, respectively, that $t = 1, E = 12, I = 0.032$

We want to find P.

$E = P*I*t$

$12 = P*0.032*1$

$P = \frac{12}{0.032}$

$P = 375$

The principal for the account is $375.

8 0

3 years ago

The equation 9t = 27.99 models a constant rate situation. HURRY PLZ

MatroZZZ [7]

9t = 27.99
5t = ?
Cross-multiply : 9t? = 139.95t
?=15.55

8 0

3 years ago

Read 2 more answers

Two hundred students are going to dine with the principal as their reward for perfect attendance. A random survey of 25 of these

Karolina [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help!

crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

4 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

5 0

3 years ago