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nekit [7.7K]
2 years ago
13

A piano string having a mass per unit length equal to 4.80 ✕ 10−3 kg/m is under a tension of 1,200 N. Find the speed with which

a wave travels on this string.
Physics
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

500 m/s

Explanation:

From the question,

V = √(T/m')................. Equation 1

Where V = Speed with which the wave travels on the string, T = Tension of the string, m' = Mass per unit length of the string.

Given: T = 1200 N, m' = 4.80×10⁻³ kg/m

Substitute these values into equation 1

V = √(1200/4.80×10⁻³)

V = √(250000)

V = 500 m/s

Hence the speed of the wave in the string is 500 m/s

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Answer:

Mistakes, chaos theory.

Explanation:

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4 0
3 years ago
Mains electricity is an ac supply. Explain the difference between direct and alternating potential difference.
Gennadij [26K]

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5 0
2 years ago
Why does ice reflect more energy compared to water?
Stells [14]

Answer:

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Explanation:

so ice reflect more energy compared to water

3 0
2 years ago
Consider an old-fashion bicycle with a small wheel of radius 0.17 m and a large wheel of radius 0.92 m. Suppose the rider starts
Gala2k [10]

Answer:

10259.6 m

Explanation:

We are given that

Radius of small wheel,r=0.17 m

Radius of large wheel,r'=0.92 m

Initial velocity,u=0

Time,t=2.7 minutes=162 s

1 min=60 s

Velocity,v=10m/s

Time,t'=13.7 minutes=822 s

Time,t''=4.1 minutes=246 s

v=u+at

Substitute the values

10=0+162a=162a

a=\frac{10}{162}=0.0617m/s^2

s=ut+\frac{1}{2}at^2

Substitute the values

s=\frac{1}{2}(0.0617)(162)^2=809.6 m

s'=vt'=10\times 822=8220 m

a'=\frac{v}{t''}=\frac{10}{246}

s''=\frac{1}{2}a't''^2=\frac{1}{2}\times \frac{10}{246}(246)^2=1230 m

Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m

6 0
3 years ago
Read 2 more answers
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