Answer:
See below
Explanation:
F = ma
7 X 10^4 = 1.05 x 10^5 * a
a = .666 = 2/3 m/s^2
Answer:
See description below
Explanation:
Given
Applied Force = 50N
Expected Appled Force = 350N
Difference = 350N - 50N
Difference = 300N
The frictional force will remain unchanged after the applied force gets to 300N.
At this point, the reason why the Net force is not zero (0) is because of the amount of force that is applied.
Also, since the frictional force is less than the applied force, the body will move in the right direction before it gets to 300 N the force of friction equals the applied force.
Answer:
t = 5.56 ms
Explanation:
Given:-
- The current carried in, Iin = 1.000002 C
- The current carried out, Iout = 1.00000 C
- The radius of sphere, r = 10 cm
Find:-
How long would it take for the sphere to increase in potential by 1000 V?
Solution:-
- The net charge held by the isolated conducting sphere after (t) seconds would be:
qnet = (Iin - Iout)*t
qnet = t*(1.000002 - 1.00000) = 0.000002*t
- The Volt potential on the surface of the conducting sphere according to Coulomb's Law derived result is given by:
V = k*qnet / r
Where, k = 8.99*10^9 ..... Coulomb's constant
qnet = V*r / k
t = 1000*0.1 / (8.99*10^9 * 0.000002)
t = 5.56 ms
Answer: A concave mirror focuses rays of light
Explanation: