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Sergeu [11.5K]
4 years ago
8

A car rolls backward from -2 to -10 m/s in 4 seconds. what is the acceleration. PLEASE HELP WILL GIVE BRAINLIEST

Physics
1 answer:
pashok25 [27]4 years ago
5 0

\bf \underline{Given : }

  • Initial velocity,u = -2 m/s

  • Final velocity,v = -10 m/s

  • Time taken, t = 4 seconds

\bf \underline{To  \: find  \: out : }

Find the acceleration ( a ) .

\bf \underline{Solution : }

We know that,

\sf \: Acceleration =  \dfrac{v - u}{t}

Substituting the values in the above formula, we get

\implies \sf \: Acceleration =  \dfrac{ - 10 - ( - 2)}{4}

\implies\sf \: Acceleration =  \dfrac{ - 10 + 2}{4}

\implies \sf \: Acceleration = \cancel  \dfrac{ - 8}{4}

\implies\sf \: Acceleration =  - 2 \: ms {}^{ - 2}

Hence,the acceleration of a body is -2 m/s².

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A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the ac
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Answer:

a = 0.50 m/s²

v = 6.0 m/s

Explanation:

Step 1: Given data

  • Initial velocity (u): 0 m/s (rest)
  • Displacement of the marble (s): 36 m
  • Time elapsed (t): 12.0 s
  • Final velocity (v): ?
  • Acceleration (a): ?

Step 2: Calculate the acceleration

We will use the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 × 12.0 s + 1/2 × a × (12.0 s)²

36 m = a × 72.0 s²

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Step 3: Calculate the final velocity

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v = 0 + 0.50 m/s² × 12.0 s

v = 6.0 m/s

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