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mafiozo [28]
3 years ago
6

Find the measure of b, given = 38°, = 74°, and a = 31.

Mathematics
1 answer:
lukranit [14]3 years ago
8 0
It would help to know which side is B, can you give a chart?
And I'm on my phone, I can't comment directly on the post, unless someone can tell me how.
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Answer:

C:

Step-by-step explanation:

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Amanda was given the coordinates of the vertices of a triangle and asked to translate the figure according to the rule (x, y)--(
KiRa [710]

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A 2 4 B 124

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7 0
3 years ago
Car colors preference change over the years and according to the particular model that the customer selects. In a recent year, 1
Margarita [4]

Answer:

99.05% probabilitiy that at most six cars are black.

Step-by-step explanation:

For each luxury car, there are only two possible outcomes. Either it is black, or it is not black. The probability of a luxury car being black is independent from other luxury cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.1, n = 25

If 25 cars of that year and type are randomly selected, find the probabilitiy that at most six cars are black.

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718

P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994

P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659

P(X = 3) = C_{25,3}.(0.1)^{3}.(0.9)^{22} = 0.2265

P(X = 4) = C_{25,4}.(0.1)^{4}.(0.9)^{21} = 0.1384

P(X = 5) = C_{25,5}.(0.1)^{5}.(0.9)^{20} = 0.0646

P(X = 6) = C_{25,6}.(0.1)^{6}.(0.9)^{19} = 0.0239

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0718 + 0.1994 + 0.2659 + 0.2265 + 0.1384 + 0.0646 + 0.0239 = 0.9905

99.05% probabilitiy that at most six cars are black.

7 0
3 years ago
What is the alibraic equation to 32 ÷ 1.60
o-na [289]

Answer:

The answer is 20

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2 years ago
Read 2 more answers
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