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3 years ago

What is the value of the rational expression below when x is equal to 3 (17+x)\(x+2)

Mathematics

2 answers:

elena55 [62]3 years ago

4 0

The value of the expression is 4.

We can find this by taking the original equation and plugging in 3 every time we see an x.

$\frac{17 + x}{x + 2}$

$\frac{17 + 3}{3 + 2}$

$\frac{20}{5}$

liubo4ka [24]3 years ago

3 0

Answer:

4 is correct for this problem

Step-by-step explanation:

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The ratio of the width to the length of a rectangle is 1:3. Which of the following ratios represents a rectangle with:______.

fenix001 [56]

The question is incomplete. Here is the complete question

The ratio of the width to the length of a rectangle is 1:3. Which of the following ratios represents a rectangle with this same ratio?

Answer:

21:63

Step-by-step explanation:

The ratio of the width to the rectangle is 1:3

= 1/3

= 0.333333

From the options given we have the following ratios

=5:7

= 5/7

= 0.71428

= 6:9

= 6/9

= 0.666666

= 33:100

= 33/100

= 0.33

= 21:63

= 21/63

= 0.3333333

Hence the ratio which represents the rectangle given above is 21:63

3 0

3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

What is the solution to w - 9 = 15? 24 6 23 5

Komok [63]

Answer:

24

Step-by-step explanation:

w - 9 = 15

+9 +9

w= 24

Hope this helped you- have a good day bro cya)

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