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stiks02 [169]
3 years ago
5

What is the value of the rational expression below when x is equal to 3 (17+x)\(x+2)

Mathematics
2 answers:
elena55 [62]3 years ago
4 0

The value of the expression is 4.


We can find this by taking the original equation and plugging in 3 every time we see an x.


\frac{17 + x}{x + 2}

\frac{17 + 3}{3 + 2}

\frac{20}{5}

4

liubo4ka [24]3 years ago
3 0

Answer:

4 is correct for this problem

Step-by-step explanation:

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Taya2010 [7]
26 maybe it can be ım not sure
8 0
3 years ago
P(x) = x4 − 9x2 − 4x 12? what some roots
arlik [135]
P(x) = x^4 - 9x^2 - 4x + 12
P(1) = 1^4 - 9(1)^2 - 4(1) + 12 = 1 - 9 - 4 + 12 = 0
x = 1 is a root.
By dividing the polynomial by x - 1, gives other roots as 3 and -2
3 0
3 years ago
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7 0
3 years ago
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PLZ HELP THIS IS DUE SOON!!!!!!! Divide. Round to the nearest hundredth if necessary.
ivolga24 [154]

Answer:

10

Step-by-step explanation:

when you divide 80.88 by 8.425 you get 9.6

and since youre rounding, you can round up 6 because its higher than 5

and your final answer should be 10.

hoped this helped! :)

4 0
3 years ago
The average monthly rent for a? 1000-sq-ft apartment in a major metropolitan area from 1998 through 2005 can be approximated by
Lunna [17]

Answer:

  t = 1.107

Step-by-step explanation:

Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...

  f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)

  = 20.0568t^2 -134.7t +124.54

  = 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form

Then f''(t) = 0 when ...

  t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706

__

The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...

  t ≈ 1.107

1.1 years after the beginning of 1998 is about 1.2 months into 1999.

Rents were increasing most rapidly in early February of 1999.

8 0
3 years ago
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