What is the y-intercept of this equation? y= 5x + 2
2 answers:
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The Correct option is D). y=1x+1 And y=2x+2
Step-by-step explanation:
The equation of a line is given as y=mx+c.
where m=slope of line and c=y intercept
The slope of line is given as m=
Solving for Redline:
From the given graph, redline passes through (-1,0) and (0,1)
The slope of Redline is m=
The slope of Redline is m=
The slope of Redline is m=(1)
And Y-intercept is 1
The equation of a Redline is given as y=1x+1
Solving for Blue-line:
From the given graph, Blue-line passes through (-1,0) and (0,2)
The slope of Blue-line is m=
The slope of Blue-line is m=
The slope of Blue-line is m=(2)
And Y-intercept is 2
The equation of a Blue-line is given as y=2x+2
The Correct option is D). y=1x+1 And y=2x+2
Answer:
x = 12
Step-by-step explanation:
18:24 (comparing the same sides for the similar shapes; 18 and 24) when simplified down is equal to 3:4.
Using this 3:4 scale factor we can find the missing side x.
Solving for x :
× 16 = 12
x = 12
OR: Set up a proportion:
×
<em>cross-multiply</em>
16 × 18 = 288
24 × x = 24x
288 = 24x
x = 12
The horse traveled 439.6 feet after walking around the track 5 times
<u><em>Solution:</em></u>
Given that, horse walks around a circular track while its trainer stands in the center
The trainer is 14 feet from the horse at all times
Therefore, radius of circular track = 14 feet
The circumference of circle is the distance traveled by horse for 1 lap
<em><u>The circumference of circle is given as:</u></em>
Where, "r" is the radius and is a constant equal to 3.14
Thus the distance traveled by horse for one time in circular track is 87.92 feet
<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>
Multiply the circumference by 5
Thus the horse traveled 439.6 feet after walking around the track 5 times