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2 years ago

Find the value of the cosine

Mathematics

1 answer:

galina1969 [7]2 years ago

7 0

Answer:

I believe the answer is c

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For each of the solutions of the equations find two consecutive integers between

ale4655 [162]

Answer:

0 and 1

Step-by-step explanation:

x² = 3

take the square root of both sides

x = {-√3, √3}

x ≈ {-1.73, 1.75}

Two consecutive integers between 1.73 and 1.75

0 and 1

7 0

2 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago

A baker divides 21.4 pounds of flour equally between five recipes. How much flour did the bakery use for each recipe?

worty [1.4K]

Answer:

4.28 per recipe

Step-by-step explanation:

21.4 divided by 5 = 4.28 per recipe

4 0

2 years ago

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What is the root square

Alex777 [14]

Square root is this 4 and -4 are square roots to 16 because 4^2= 16

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3 years ago

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What is 275x56 in stander algorithm pls help

leonid [27]

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3 years ago