Answer:
d:) 1024
Step-by-step explanation:
Evaluate (4 x^3)^2 where x = 2:
(4 x^3)^2 = (4×2^3)^2
Multiply each exponent in 4×2^3 by 2:
4^2 (2^3)^2
Multiply exponents. (2^3)^2 = 2^(3×2):
2^(3×2)×4^2
4^2 = 16:
2^(3×2)×16
3×2 = 6:
2^6×16
2^6 = (2^3)^2 = (2×2^2)^2:
(2×2^2)^2 16
2^2 = 4:
(2×4)^2 16
2×4 = 8:
8^2×16
8^2 = 64:
64×16
| | 6 | 4
× | | 1 | 6
| 3 | 8 | 4
| 6 | 4 | 0
1 | 0 | 2 | 4:
Answer: 1024
Answer:
Hi! The answer to your question is Rectangle
Step-by-step explanation:
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Answer:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
Step-by-step explanation:
This is the fibonacci sequence with each term times x.
Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.
That is:
1x+1x=2x
1x+2x=3x
2x+3x=5x
3x+5x=8x
So since we need the two terms before the third per each consecutive triple in the sequence, our recursive definition must include two terms of the sequence. People normally go with the first two.
f(1)=1x since first term of f is 1x
f(2)=1x since second term of f is 1x
Yes, I'm naming the sequence f.
So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...
Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.
So in general f(n)=f(n-1)+f(n-2).
So the full recursive definition is:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
Answer:
750 minutes
Step-by-step explanation:
Answer:
5 units
Step-by-step explanation:
If point T is on the line segment SU, then ST + TU = SU.
Given
TU = 4x + 1
SU = 8
ST = 3x
To get TU, we need to get the value of x first. To get x, we will substitute the given parameters into the formula;
3x+4x+1 = 8
7x+1 = 8
subtract 1 from both sides
7x+1-1 = 8-1
7x = 7
divide both sides by 7
7x/7 = 7/7
x = 1
Substitute x = 1 into the length TU
Since TU = 4x+1
TU = 4(1)+1
TU = 5
Hence the numerical length of TU is 5 units
