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eimsori [14]
2 years ago
14

Simplfy: -1| 2/3 - 4| / 5/6

Mathematics
2 answers:
never [62]2 years ago
7 0

Step-by-step explanation:

-1| 2/3 - 4| / 5/6

=-1 paxi ko sign k hola

sweet-ann [11.9K]2 years ago
7 0

1) Simplify \frac{2}{3} -4 to -\frac{10}{3}

-1×|-10/3|x5/6

2) simplify |-10/3| to 10/3

-1x10/3x5/6

3) use this rule: a/b x c/d = ac/bd

-1x10x5/3x6

4) simplify 1 x 10 to 10

-10x5/3x6

5) simplify 10 x 5 to 50

-50/3x6

6) simplify 3 x 6 to 18

-50/18

simplify 50/18 to 25/9

-25/9 is the answer

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280

Step-by-step explanation:

3 0
3 years ago
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There are 4 students on a team for a relay race. How many teams can be made from 27 students?
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Keisha says that all functions are relations but not all relations are functions. kevin says that all relations are functions bu
vladimir1956 [14]

Keisha is correct, because as per the definition <u>A function is a special relationship where each input has a single output</u>.

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3 0
3 years ago
Which is the equation of a line that has a slope of -2/3 and passes through point (-3, -1)? y=-2/3x+1.
bazaltina [42]

Answer:

y = -2/3x - 3

Step-by-step explanation:

First, write the equation using the slope. It should look like this: y = -2/3x + b. Next, find the y intercept by plugging in the point. This is what it looks like: -1 = -2/3(-3) + b. Multiply -2/3 by -3 to get 2. This is what it should look like now: -1 = 2 + b. Subtract 3 from both sides to get -3 = b. Go back to your original equation and plug in -3 for b. This is your final equation:

y = -2/3x - 3

Hope this helped! :)

7 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
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